Mechanics and Engineers Book of Reference and Engineers Field BookStringer & Townsend, 1856 - 517 σελίδες |
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Σελίδα x
... sine given , 10. To find the area of a parabola , or its segment , 12. To find the area of a segment of a circle , 13. To find the area of a circular ring or space included between two concentric circles , 28 29 30 31 31 **** 235 555 88 ...
... sine given , 10. To find the area of a parabola , or its segment , 12. To find the area of a segment of a circle , 13. To find the area of a circular ring or space included between two concentric circles , 28 29 30 31 31 **** 235 555 88 ...
Σελίδα 28
... SINE is a line drawn from the middle of a chord per- pendicular to the circumference . A SECTOR of a circle is a figure contained by two radii and an arc , as ACBE . PROBLEM I To find the area of any parallelogram . RULE . Multiply the ...
... SINE is a line drawn from the middle of a chord per- pendicular to the circumference . A SECTOR of a circle is a figure contained by two radii and an arc , as ACBE . PROBLEM I To find the area of any parallelogram . RULE . Multiply the ...
Σελίδα 32
... sine given . RULE . Divide the square of half the chord by the versed sine , to the quotient of which add the versed sine , and 32 MENSURATION .
... sine given . RULE . Divide the square of half the chord by the versed sine , to the quotient of which add the versed sine , and 32 MENSURATION .
Σελίδα 33
... sine be divided by the versed sine , the quotient will be the diameter of the circle to which that segment corresponds . EXAMPLE . Given the chord AB 24 , and versed sine CD = 8 ; required the diameter of the circle CE = Half the chord ...
... sine be divided by the versed sine , the quotient will be the diameter of the circle to which that segment corresponds . EXAMPLE . Given the chord AB 24 , and versed sine CD = 8 ; required the diameter of the circle CE = Half the chord ...
Σελίδα 34
... sine by the decimal 626 , to the square of the product add the square of half the chord ; multiply twice the square root of the sum by of the versed sine , and the product will be the area . EXAMPLE . Required the area of a segment of a ...
... sine by the decimal 626 , to the square of the product add the square of half the chord ; multiply twice the square root of the sum by of the versed sine , and the product will be the area . EXAMPLE . Required the area of a segment of a ...
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Συχνά εμφανιζόμενοι όροι και φράσεις
9 Diff acid angle antimony applied beam bismuth blue body Boil borax Brass breadth cast-iron centre chord circle circumference color Copal copper cosine cube curvature curve cylinder DEGREES Diam diameter Dissolve distance divide draw equal EXAMPLE external secant feet radius foot force gallons given glass glue gold heat horse power inclined plane iron lamp-black length lever linseed oil Logarithm Marble mastic Melt Metal minute Multiply nitric acid number of teeth ounces paper pearlash perpendicular piece of timber pint potash pounds pressure Prussian blue quantity quotient rectified spirit revolutions per minute revolving RULE sal-ammoniac shaft shell-lac side silver solution specific gravity spirit square inch square root steam sulphate surface TABLE tangent tenon thickness tons Varnish velocity versed sine vessel vinegar weight wheel wood yellow zinc
Δημοφιλή αποσπάσματα
Σελίδα 39 - To find the solidity of a spheroid. RULE. Multiply the square of the revolving axis by the fixed axis, and by *5236, and the product will be the solidity.
Σελίδα 33 - Any circle whose diameter is double that of another contains four times the area of the other.
Σελίδα 27 - Of four-sided figures, a square is that which has all its sides equal, and all its angles right angles.
Σελίδα 267 - ... they are dissolved. Then mix the whole with a sufficient heat. Keep the glue in a phial closely stopped, and when it is to be used, set the phial in boiling water.
Σελίδα 266 - ... and, in another vessel, dissolve as much isinglass, previously a little softened in water, (though none of the water must be used), in French brandy or good rum, as will make a...
Σελίδα 235 - SOLDERS. For Lead. — Melt one part of block tin, and, when in a state of fusion, add 2 parts of lead. Resin should be used with this solder. For Tin. — Pewter, 4 parts ; tin, 1 ; bismuth, 1. Melt them together and run them into slips.
Σελίδα 38 - RULE. — To the sum of the areas of the two ends add the square root of their product ; multiply this sum by the perpendicular height, and -^ of the product is the solid content.
Σελίδα 128 - Bring the edges of the pieces of shell to fit each other, observing to give the same inclination of grain to each, then secure them in a piece of paper, and place them between hot irons or pincers ; apply pressure, and let them cool.
Σελίδα 65 - RULE. — Divide the weight to be raised by twice the number of pulleys in the lower block ; the quotient will give the power necessary to raise the weight. EXAMPLE. — What power is required to raise 600 Ibs., when the lower block contains six pulleys ? 600 6 x 2 = 50 Iks., Ans.
Σελίδα 53 - To find the centre of Gyration, multiply the weight of the several particles by the squares of their distances from the centre of motion, and divide the sum of the products by the weight of the whole mass; the square root of the quotient will be the distance of the centre of gyration, from the centre of motion.