 | Anthony Nesbit - 1824 - 476 σελίδες
...the perpendicular height 9 feet ? Ans. 82.6875 feet. PROBLEM X. To find the solidity of a prismoid. RULE. To the sum of the areas of the two ends add four times the area of a section parallel to and equally distant from both ends ; multiply this sum... | |
 | John Bonnycastle - 1829 - 256 σελίδες
...perpendicular height to be 17.14508 inches ? Ans. 3.1006 feet. PROBLEM XI. To find the solidity ofaprismoid. . RULE.* To the sum of the areas of the two ends add four times the area of a section parallel tq and equally distant from both ends, and this last sum... | |
 | Thomas Curtis - 1829 - 810 σελίδες
...9 ,4/1 ~ = 7140 solid inches, or 4-1319 solid feet. PROB. XXIX. To find the solidity of a promoid. Rule,— to the sum of the areas of the two ends add four times the area of a section parallel to, and equally distant from, both ends, and multiply the... | |
 | John Bonnycastle - 1833 - 310 σελίδες
...perpendicular height to be 17. 14508 inches? Ans. 3.1006/ee<. PROBLEM XI. To find the solidity of a primoid. RULE.* To the sum of the areas of the two ends add four times the area of a section parallel to and equally distant from both ends, and this last sum... | |
 | William Templeton (engineer.) - 1833 - 224 σελίδες
...gallons nearly. Or, 13238.7024 x '.003607 = 47.75 gallons nearly as before. •» «bi2&' PROBLEM V. To find the Solid Content of the Frustum of a Pyramid....multiply this sum by the perpendicular height ; and i of the product is the solid content. EXAMPLE. — Required the solid content of the frustum of a... | |
 | Samuel YOUNG (of Manchester.) - 1833 - 272 σελίδες
...•f)l foot. PROBLEM III. To find the solidity of timber broader at one end than the other. RULE. To the areas of the two ends add the square root of their Product, which multiplied by ^ of the length will give the solidity. 9. a. . «. 6. 7. 8. 10. 11. 10 ... 12... | |
 | Tobias Ostrander - 1834 - 182 σελίδες
...prismoid when its ends are right parallelograms. ~ ~ " PROBLEM XVIII. To find the solidity of a prismoid. Rule — To the sum of the areas of the two ends, add four times the area of a section parallel to, and equally distant from, both ends, arid this last sum... | |
 | J. M. Scribner - 1844 - 130 σελίδες
...inches 1 Jlns. 32552 cubic ft. PROBLEM VIII. To find the Solidity of a Rectangular Prismoid. AKT. 45. Rule. — To the sum of the areas of the two ends add four times the area of a section parallel to and equally distant from the parallel ends, and this sum,... | |
 | William Watson (of Beverley.) - 1845 - 188 σελίδες
...height 25. Ans. surf. 1363.4544, sol. 3493.4592. PROBLEM 6. — To find the solidity of a prismoid. RULE. — To the sum of the areas of the two ends, add four times the area of a section parallel to, and equally distant from both ; this sum multiplied by... | |
 | Scottish school-book assoc - 1845 - 444 σελίδες
...perpendicular height 28 inches? Ans. 3 feet 444 inches. PROBLEM VII. To find the solidity of a prismoid. RULE. To the sum of the areas of the two ends add four times the area of a section, parallel to and equally distant from both ends ; multiply this sum... | |
| |
RULE. — To the sum of the areas of the two ends add the square root of their product ; multiply this sum by the perpendicular height, and -^ of the product is the solid content. 
