Elements of geometry, containing books i. to vi.and portions of books xi. and xii. of Euclid, with exercises and notes, by J.H. SmithRivingtons, 1876 - 349 σελίδες |
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Αποτελέσματα 1 - 5 από τα 30.
Σελίδα 77
... rect . ABCD = rect . EFGH . For if the rect . EFGH be applied to the rect . ABCD , so that EF coincides with AB , then FG will fall on BC , . △ EFG = 4 ABC , and G will coincide with C , · BC = FG . Similarly it may be shewn that H ...
... rect . ABCD = rect . EFGH . For if the rect . EFGH be applied to the rect . ABCD , so that EF coincides with AB , then FG will fall on BC , . △ EFG = 4 ABC , and G will coincide with C , · BC = FG . Similarly it may be shewn that H ...
Σελίδα 78
... rect . AB , CE and rect . AB , EF and rect . AB , FD . From C draw CG 1 to CD , and in CG make CH = AB . Through H draw HM || to CD . Through E , F , and D draw EK , FL , DM || to CH . Then EK and FL , being each = CII , are each = AB ...
... rect . AB , CE and rect . AB , EF and rect . AB , FD . From C draw CG 1 to CD , and in CG make CH = AB . Through H draw HM || to CD . Through E , F , and D draw EK , FL , DM || to CH . Then EK and FL , being each = CII , are each = AB ...
Σελίδα 79
... rect . AB , AC and rect . AB , CB . On AB describe the sq . ADEB I. 46 . Through C draw CF | to AD . I. 31 . = Then AE sum of AF and CE . Now AE is the sq . on AB , AF = rect . AB , AC , ·· AD = AB , CE = rect . AB , CB , · BE = AB ...
... rect . AB , AC and rect . AB , CB . On AB describe the sq . ADEB I. 46 . Through C draw CF | to AD . I. 31 . = Then AE sum of AF and CE . Now AE is the sq . on AB , AF = rect . AB , AC , ·· AD = AB , CE = rect . AB , CB , · BE = AB ...
Σελίδα 80
... rect . AB , CB = sum of rect . AC , CB and sq . on CB . On CB describe the sq . CDEB . I. 46 . From A draw AF || to CD , meeting ED produced in F. Then AE = = sum of AD and CE . Now AE - rect . AB , CB , :: BE = CB , AD = rect . AC , CB ...
... rect . AB , CB = sum of rect . AC , CB and sq . on CB . On CB describe the sq . CDEB . I. 46 . From A draw AF || to CD , meeting ED produced in F. Then AE = = sum of AD and CE . Now AE - rect . AB , CB , :: BE = CB , AD = rect . AC , CB ...
Σελίδα 81
... rect . AC , CB , :: CF = CB , FE = rect . AC , CB , FG - AC and FK = CB . .. sq . on AB = sum of sqq . on AC , CB and twice rect . AC , CB . Q. E. D. Ex . In a triangle , whose vertical angle is a right angle , a straight line is drawn ...
... rect . AC , CB , :: CF = CB , FE = rect . AC , CB , FG - AC and FK = CB . .. sq . on AB = sum of sqq . on AC , CB and twice rect . AC , CB . Q. E. D. Ex . In a triangle , whose vertical angle is a right angle , a straight line is drawn ...
Συχνά εμφανιζόμενοι όροι και φράσεις
AB=DE ABCD AC=DF angles equal angular points base BC BC=EF centre chord circumference coincide described diagonals diameter divided equal angles equiangular equilateral triangle equimultiples Eucl Euclid exterior angle given angle given circle given point given st given straight line greater than nD hypotenuse inscribed intersect isosceles triangle less Let ABC Let the st lines be drawn magnitudes middle points multiple opposite angles opposite sides parallelogram pentagon perpendicular produced Prop prove Q. E. D. Ex Q. E. D. PROPOSITION quadrilateral radius ratio rect rectangle contained reflex angle rhombus right angles segment shew shewn straight line joining subtended sum of sqq Take any pt tangent THEOREM together=two rt trapezium triangle ABC triangles are equal vertex vertical angle
Δημοφιλή αποσπάσματα
Σελίδα 23 - To draw a straight line perpendicular to a given straight line of an unlimited length, from a given point without it. Let AB be the given straight line, which may be produced to any length both ways, and let c be a point without it. It is required to draw a straight line perpendicular to AB from the point c. Take any point D upon the other side of AB, and from the centre c, at the distance CD, describe (Post.
Σελίδα 82 - If a straight line be divided into two equal parts, and also into two unequal parts, the rectangle contained by the unequal parts, together with the square on the line between the points of section, is equal to the square on half the line.
Σελίδα 40 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. either the sides adjacent to the equal...
Σελίδα 161 - The angle in a semicircle is a right angle; the angle in a segment greater than a semicircle is less than a right angle; and the angle in a segment less than a semicircle is greater than a right angle.
Σελίδα 91 - In every triangle, the square on the side subtending either of the acute angles, is less than the squares on the sides containing that angle, by twice the rectangle contained by either of these sides, and the straight line intercepted between the acute angle and the perpendicular let fall upon it from the opposite angle, Let ABC be any triangle, and the angle at B one of its acute angles, and upon BC, one of the sides containing it, let fall the perpendicular AD from the opposite angle.
Σελίδα 5 - A circle is a plane figure contained by one line, which is called the circumference, and is such that all straight lines drawn from a certain point within the figure to the circumference, are equal to one another.
Σελίδα 5 - A diameter of a circle is a straight line drawn through the centre, and terminated both ways by the circumference.
Σελίδα 35 - ... shall be equal to three given straight lines, but any two whatever of these must be greater than the third.
Σελίδα 90 - ... the sides containing the obtuse angle, by twice the rectangle contained by the side upon which, when produced, the perpendicular falls, and the straight line intercepted without the triangle between the perpendicular and the obtuse...
Σελίδα 265 - EQUAL parallelograms which have one angle of the one equal to one angle of the other, have their sides about the equal angles...