Elements of geometry: consisting of the first four,and the sixth, books of Euclid, with the principal theorems in proportion [&c.] by J. Narrien1842 |
Αναζήτηση στο βιβλίο
Αποτελέσματα 1 - 5 από τα 49.
Σελίδα
... reason for adopting a method different from that of Euclid , in treating the subject of proportion among geometrical mag- nitudes . Magnitudes in the abstract , when compared with one another in respect of their extent , are divided ...
... reason for adopting a method different from that of Euclid , in treating the subject of proportion among geometrical mag- nitudes . Magnitudes in the abstract , when compared with one another in respect of their extent , are divided ...
Σελίδα 7
... reason last mentioned , the thirteenth definition is so marked : the nineteenth , properly belongs to the third book , where it is repeated . PROPOSITION I. PROBLEM . To describe an equilateral triangle upon B 4 EUC . B. I. OF GEOMETRY ...
... reason last mentioned , the thirteenth definition is so marked : the nineteenth , properly belongs to the third book , where it is repeated . PROPOSITION I. PROBLEM . To describe an equilateral triangle upon B 4 EUC . B. I. OF GEOMETRY ...
Σελίδα 21
... opposite angle , the exterior angle BDC of the triangle CDE is greater than CED ; for the same reason , the exterior angle CEB of the triangle ABE C 3 EUC . B. I. 21 OF GEOMETRY . Let ABC be a triangle; any two sides of ...
... opposite angle , the exterior angle BDC of the triangle CDE is greater than CED ; for the same reason , the exterior angle CEB of the triangle ABE C 3 EUC . B. I. 21 OF GEOMETRY . Let ABC be a triangle; any two sides of ...
Σελίδα 22
Euclides John Narrien. reason , the exterior angle CEB of the triangle ABE is greater than BAC ; and it has been demonstrated that the angle BDC is greater than the angle CEB ; much more then is the angle BDC greater than the angle BAC ...
Euclides John Narrien. reason , the exterior angle CEB of the triangle ABE is greater than BAC ; and it has been demonstrated that the angle BDC is greater than the angle CEB ; much more then is the angle BDC greater than the angle BAC ...
Σελίδα 33
... reason , the parallelogram EFGH is equivalent to the same EBCH : therefore , also , the parallelogram ABCD is equal or equivalent to EFGH . Wherefore parallelograms , & c . Q. E. D. PROP . XXXVII . THEOR . TRIANGLES upon the same base ...
... reason , the parallelogram EFGH is equivalent to the same EBCH : therefore , also , the parallelogram ABCD is equal or equivalent to EFGH . Wherefore parallelograms , & c . Q. E. D. PROP . XXXVII . THEOR . TRIANGLES upon the same base ...
Άλλες εκδόσεις - Προβολή όλων
Elements of Geometry: Consisting of the First Four, and the Sixth, Books of ... Euclides Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2015 |
Elements of Geometry: Consisting of the First Four, and the Sixth, Books of ... Euclides Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2018 |
Elements of Geometry: Consisting of the First Four,and the Sixth, Books of ... Euclides Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2013 |
Συχνά εμφανιζόμενοι όροι και φράσεις
ABCD AC is equal adjacent angles altitudes angle ABC angle ACB angle BAC assigned base BC bisected centre circle ABC circumference cone convex surface cylinder described diameter draw drawn duplicate ratio Edition equal angles equal or equivalent equi equilateral and equiangular Euclid exterior angle fore given line given rectilineal given straight line gnomon greater Greek homologous homologous sides inscribed join Latin Let ABC measure number of sides opposite angles parallel parallelepiped parallelogram perpendicular picket plane angles prism PROB proportional proposition pyramid Q. E. D. PROP rectangle contained rectilineal figure regular polygon remaining angle right angles segment similar solid angle sphere spherical angle square of AC straight line AC THEOR touches the circle triangle ABC triangle DEF wherefore
Δημοφιλή αποσπάσματα
Σελίδα 55 - In every triangle, the square of the side subtending either of the acute angles is less than the squares of the sides containing that angle, by twice the rectangle contained by either of these sides, and the straight line intercepted between the perpendicular let fall upon it from the opposite angle, and the acute angle.
Σελίδα 47 - CB ; wherefore the four figures HF, CK, AG, GE are equal to the squares of AC, CB, and to twice the rectangle AC, CB : but HF, CK, AG, GE make up the whole figure ADEB, which is the square of AB: therefore the square of AB is equal to the squares of AC, CB, and twice the rectangle AC, CB. Wherefore, if a straight line, &c.
Σελίδα 12 - UPON the same base, and on the same side of it, there cannot be two triangles that have their sides which are terminated in one extremity of the base equal to one another, and likewise those which are terminated in the other extremity...
Σελίδα 73 - CBED is greater than a semicircle, the angles CAD, CED are equal : therefore the whole angle BAD is, equal to the whole angle BED.
Σελίδα 8 - A New Treatise on the Use of the Globes ; or, a Philosophical View of the Earth and Heavens : comprehending an Account of the Figure, Magnitude, and Motion of the Earth: with the Natural Changes of its Surface, caused by Floods, Earthquakes, &c.
Σελίδα 142 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Σελίδα 11 - ABC is therefore equal to the remaining angle ACB, which are the angles at the base of the triangle ABC : And it has also been proved that the angle FBC is equal to the angle GCB, which are the angles upon the other side of the base. Therefore, " the angles at the base
Σελίδα 53 - AB be the given straight line ; it is required to divide it into two parts, so that the rectangle contained by the whole, and one of the parts, shall be equal to the square of the other part.
Σελίδα 30 - All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sidef. For any rectilineal figure ABCDE can be divided into as many triangles as the figure has sides, by drawing straight lines from a point F within the figure to each of its angles.
Σελίδα 9 - If two triangles have two sides of the one equal to two sides of the...