Elements of Geometry: With, Practical Applications |
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Σελίδα 39
A straight line being drawn in a direction perpendicular to that in which the
parallels are required to be drawn , the cross - piece of the T - square is laid upon
this line , and the piece at right - angles to it gives the direction of the parallels .
A straight line being drawn in a direction perpendicular to that in which the
parallels are required to be drawn , the cross - piece of the T - square is laid upon
this line , and the piece at right - angles to it gives the direction of the parallels .
Σελίδα 61
The area of the triangle ABC is equal to JAC.BC ; therefore the area of the four
triangles is equal to 2 AC.BC , which , added to the area of the internal square ,
gives AC ? + BC2 for the area of the entire square ABDF ; but the area of this
square ...
The area of the triangle ABC is equal to JAC.BC ; therefore the area of the four
triangles is equal to 2 AC.BC , which , added to the area of the internal square ,
gives AC ? + BC2 for the area of the entire square ABDF ; but the area of this
square ...
Σελίδα 66
... the difference of two quantities added to half their sum gives the greater , we
have , in both cases , c2 - d b AD , the greater segment . 26 tă Again , CD = VAC
? – AD2 ; that 66 ELEMENTS OF GEOMETRY .
... the difference of two quantities added to half their sum gives the greater , we
have , in both cases , c2 - d b AD , the greater segment . 26 tă Again , CD = VAC
? – AD2 ; that 66 ELEMENTS OF GEOMETRY .
Σελίδα 132
For , drawing AD and AC , the triangles ABD and ABC will have the angle at B
common ; the angle BAD is equal to BCA , ( B. III , Prop . viir ; ) therefore the two
triangles are similar , and we have BC : BA :: BA : BD . which immediately gives
BA ...
For , drawing AD and AC , the triangles ABD and ABC will have the angle at B
common ; the angle BAD is equal to BCA , ( B. III , Prop . viir ; ) therefore the two
triangles are similar , and we have BC : BA :: BA : BD . which immediately gives
BA ...
Σελίδα 135
The above equation readily gives h = žda . Hence , if we know the distance to a
point in the horizon , in miles , we may find our height , in feet , by taking two -
thirds of the square of this distance . As an example , suppose the eye of an
observer ...
The above equation readily gives h = žda . Hence , if we know the distance to a
point in the horizon , in miles , we may find our height , in feet , by taking two -
thirds of the square of this distance . As an example , suppose the eye of an
observer ...
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Συχνά εμφανιζόμενοι όροι και φράσεις
ABCD altitude angle base bisect called centre chord circ circle circumference circumscribed coincide common cone consequently construction contained convex corresponding cylinder denote described diagonal diameter difference distance divided double draw equal equilateral equivalent exterior angle extremities figure follows formed four given gives greater hence included inscribed intersection join length less lines drawn magnitude manner mean measured measured by half meet multiplied opposite parallel parallel planes parallelogram parallelopipedon pass perimeter perpendicular plane plane MN polygon portion position prism PROBLEM produced Prop proportional PROPOSITION pyramid radii radius ratio rectangle remain respectively right-angles sector segment shown sides similar solid angle sphere spherical square straight line suppose surface taken tangent THEOREM third triangle ABC vertex VIII whole zone
Δημοφιλή αποσπάσματα
Σελίδα 231 - THE sphere is a solid terminated by a curve surface, all the points of which are equally distant from a point within, called the centre.
Σελίδα 147 - PROBLEM. To inscribe a circle in a given triangle. Let ABC be the given triangle : it is required to inscribe a circle in the triangle ABC.
Σελίδα 17 - A circle is a plane figure contained by one line, which is called the circumference, and is such, that all straight lines drawn from a certain point within the figure to the circumference are equal to one another.
Σελίδα 28 - If two sides and the included angle of the one are respectively equal to two sides and the included angle of the other...
Σελίδα 233 - The volume of a cylinder is equal to the product of its base by its altitude. Let the volume of the cylinder be denoted by V, its base by B, and its altitude by H.
Σελίδα 276 - THEOREM. Two triangles on the same sphere, or on equal spheres, are equal in all their parts, when they have each an equal angle included between equal sides. Suppose the side...
Σελίδα 120 - The areas of two triangles which have an angle of the one equal to an angle of the other are to each other as the products of the sides including the equal angles. D c A' D' Hyp. In triangles ABC and A'B'C', ZA = ZA'. To prove AABC = ABxAC. A A'B'C' A'B'xA'C' Proof. Draw the altitudes BD and B'D'.
Σελίδα 18 - If equals be added to unequals, the wholes are unequal. V. If equals be taken from unequals, the remainders are unequal. VI. Things which are double of the same, are equal to one another.
Σελίδα 232 - A spherical triangle is a portion of the surface of a sphere, bounded by three arcs of great circles.
Σελίδα 96 - Similar figures, are those that have all the angles of the one equal to all the angles of the other, each to each, and the sides about the equal angles proportional.
Πληροφορίες βιβλιογραφίας
| Τίτλος | Elements of Geometry: With, Practical Applications |
| Συγγραφέας | George Roberts Perkins |
| Εκδότης | D. Appleton and Company, 1850 |
| Πρωτότυπο από | Πανεπιστήμιο Χάρβαρντ |
| Ψηφιοποιήθηκε στις | 1 Μαρ. 2007 |
| Μέγεθος | 320 σελίδες |
| Εξαγωγή αναφοράς | BiBTeX EndNote RefMan |