An Elementary Treatise of the Application of Trigonometry to Orthographic and Stereographic Projection, Dialling, Mensuration of Heights and Distances, Navigation, Nautical Astronomy, Surveying and Levelling: Together with Logarithmic and Other Tables; Designed for the Use of the Students of the University of Cambridge, New England

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Hilliard, Gray, 1840 - 155 σελίδες
 

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Σελίδα 24 - ... is, in the plane of the meridian, and making an angle with the horizon equal to the latitude of the place.
Σελίδα 81 - Method of correcting the apparent distance of the Moon from the Sun, or a Star, for the effects of Parallax and Refraction.
Σελίδα 30 - It is required to find the perpendicular height of a cloud or other object, when its angles of elevation, as taken by two observers at the same time, on the same side of it, and in the same vertical plane, were 64° and 35°, their distance apart being half a mile, or 880 yards. It is evident from figure 28, that this problem may be solved in the same manner as the last.
Σελίδα 98 - ... or from the surface of a tranquil fluid, supposed to be situated immediately above or below them. A level surface, therefore, is one that is every where perpendicular to a plumb-line, or the radius of the earth considered as a sphere. This is called a true level, while a straight line or plane that...
Σελίδα 31 - To prove that the exterior angle of a triangle is equal to the sum of the two interior opposite angles (see fig.
Σελίδα 110 - But this multiplier is constant only when the mean temperature of the air at the two stations is the same ; and for a lower temperature the multiplier is less, and for a higher it is greater. A correction, however, may be applied for any deviation from an assumed temperature, by increasing or diminishing (according as the temperature is higher or lower) the approximate height by its 4491A part for each degree of Fahrenheit's thermometer.
Σελίδα 86 - ABCD (Jig. 64), the breadth or perpendicular distance of either two opposite sides, as CP, is equal to the product of the corresponding oblique side CB by the sine of the angle of the parallelogram, radius being unity (Trig. 30). Hence, the area of a parallelogram is equal to the product of any two contiguous sides multiplied by the sine of the contained angle, radius being unity. Given AB = 59 chains 80 links, or...
Σελίδα 11 - If two triangles have two sides of the one respectively equal to two sides of the other, and the contained angles supplemental, the two triangles are equal.

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