 Divide the greater number by the less, the divisor by the remainder, and thus continue to divide the last divisor by the last remainder until there is no remainder ; the last divisor will be the greatest common divisor.  The Packard Commercial Arithmetic - Σελίδα 5των Silas Sadler Packard, Byron Horton - 1882 - 204 σελίδεςΠλήρης προβολή - Σχετικά με αυτό το βιβλίο
 | 1867 - 964 σελίδες
...KULE. — Divide tho greater by the loss, then the preceding divisor by the remainder, and so on, nntil there is no remainder. The last divisor will be the greatest common measure required. EXAMPLE. — To find tho greatest common measure of 532 and 1274. Arrange the process... | |
 | David Steel - 1805 - 392 σελίδες
...common measure, divide the greater number by the lesser, and the last divisor by the remainder till there is no remainder; the last divisor will be the greatest common measure. EXAMPLE I. Reduce the fraction 4f£f *° 'ts lowest terms. 9767-7-4418=2, remainder 931. 4418-7-931=4,... | |
 | William Foster - 1840 - 92 σελίδες
...letter : divide the greater by the less, and the preceding divisor by the last remainder, and so on till there is no remainder, the last divisor will be the greatest common measure. Ex. Find the greatest common measure of 2« + 1 + -r' and 2*4 ¿"+2*+ 1. We arrange the quantities... | |
 | Davis Wasgatt Clark - 1844 - 394 σελίδες
...remainder, divide the first divisor by this remainder. 3. Continue to divide in the same manner till there is no remainder ; the last divisor will be the greatest common measure. Note 1. — If, in the course of the reduction, one factor is found to be common to all the... | |
 | George Roberts Perkins - 1846 - 266 σελίδες
...the less numbtr by the remainder ; thus continue to divide the last divisor by the last remainder, until there is no remainder. The last divisor will be the greatest common divisor. NOTE. — When there are more than two numbers whoae greatest common divisor is required, we must first... | |
 | Frederic A. Adams - 1846 - 230 σελίδες
...less, and then take the divisor for a new dividend, and divide it by the remainder, and so on, till there is no remainder ; the last divisor will be the greatest common divisor. . i Apply the above rule to the sixth example. 187)221(1 187 ~34"U87C5 greatest common divisor i<^... | |
 | Davis Wasgatt Clark - 1846 - 374 σελίδες
...remainder, divide the first divisor by this remainder. 3. Continue to divide in the same manner till there is no remainder ; the last divisor will be the greatest common measure. Note 1.—If, in the course of the reduction, one factor is found to be common to all the... | |
 | George Roberts Perkins - 1849 - 346 σελίδες
...the less number by the remainder ; thus continue to divide the last divisor by the last remainder, until there is no remainder. The last divisor will be the greatest common divisor. NOTE. — When there are more than two numbers whose greatest common divisor is required, we must find... | |
 | George Roberts Perkins - 1850 - 364 σελίδες
...the less number by the remainder ; thus continue to divide the last divisor by the last remainder, until there is no remainder. The last divisor will be the greatest common divisor. NOTE. — When there are more than two numbers whose greatest common divisor is required, we must find... | |
 | George Roberts Perkins - 1851 - 356 σελίδες
...then the less number by the remainder; thus continue to divide the last divisor by the last remainder, until there is no remainder. The last divisor will be the greatest common divisor. » NOTE.—When there are more than two numbers whose greatest common divisor is required, we must... | |
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