Pure mathematics, Τόμος 11874 |
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Αποτελέσματα 1 - 5 από τα 33.
Σελίδα 102
... ( Const . ) , and AF is common to the two triangles DAF , EAF ; The two sides DA , AF are equal to the two sides EA , AF , each to each ; And the base DF is equal to the base EF ( Const . ) ; Therefore the angle DAF is equal to the angle ...
... ( Const . ) , and AF is common to the two triangles DAF , EAF ; The two sides DA , AF are equal to the two sides EA , AF , each to each ; And the base DF is equal to the base EF ( Const . ) ; Therefore the angle DAF is equal to the angle ...
Σελίδα 103
... ( Const . ) , and CD common to the two triangles ACD , BCD ; The two sides AC , CD are equal to the two sides BC , CD , each to each ; And the angle ACD is equal to the angle BCD ( Const . ) ; Therefore the base AD is equal to the base DB ...
... ( Const . ) , and CD common to the two triangles ACD , BCD ; The two sides AC , CD are equal to the two sides BC , CD , each to each ; And the angle ACD is equal to the angle BCD ( Const . ) ; Therefore the base AD is equal to the base DB ...
Σελίδα 104
... ( I. 10 ) . Join CF , CH , CG . Then CH shall be perpendicular to AB . PROOF . - Because FH is equal to HG ( Const . ) , and HC common to the two triangles FHC , GHC ; The two sides FH , HC are equal to the 104 GEOMETRY .
... ( I. 10 ) . Join CF , CH , CG . Then CH shall be perpendicular to AB . PROOF . - Because FH is equal to HG ( Const . ) , and HC common to the two triangles FHC , GHC ; The two sides FH , HC are equal to the 104 GEOMETRY .
Σελίδα 108
... ( Const . ) , AE , EB are equal to CE , EF , each to each ; And the angle AEB is equal to the angle CEF , because they are opposite vertical angles ( I. 15 ) . Therefore the base AB is equal to the base CF ( I. 4 ) ; And the triangle AEB ...
... ( Const . ) , AE , EB are equal to CE , EF , each to each ; And the angle AEB is equal to the angle CEF , because they are opposite vertical angles ( I. 15 ) . Therefore the base AB is equal to the base CF ( I. 4 ) ; And the triangle AEB ...
Σελίδα 112
... ( Const . ) ; Therefore FK is equal to A ( Ax . 1 ) . Again , because the point G is the centre of the circle HLK , GH is equal to GK ( Def . 15 ) . But GH is equal to C ( Const . ) ; Therefore GK is equal to C ( Ax . 1 ) , And FG is ...
... ( Const . ) ; Therefore FK is equal to A ( Ax . 1 ) . Again , because the point G is the centre of the circle HLK , GH is equal to GK ( Def . 15 ) . But GH is equal to C ( Const . ) ; Therefore GK is equal to C ( Ax . 1 ) , And FG is ...
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amount base called cent centre circle common Const contained decimal denominator describe difference distance divided divisible divisor double draw drawn equal equation evident example expression factor figures Find four fraction give given greater half Hence hour integer interest join less letters logarithm measure meet metres miles Multiply negative obtained opposite parallel parallelogram pass perpendicular places positive PROOF.-Because Q. E. D. Proposition quantity quotient ratio rectangle Reduce remainder respectively result right angles rule segment sides square square root straight line subtraction third touch triangle twice units whole
Δημοφιλή αποσπάσματα
Σελίδα 272 - The angles in the same segment of a circle are equal to one another.
Σελίδα 103 - When a straight line standing on another straight line makes the adjacent angles equal to one another, each of the angles is called a right angle; and the straight line which stands on the other is called a perpendicular to it.
Σελίδα 233 - If there be two straight lines, one of which is divided into any number of parts, the rectangle contained by the two straight lines is equal to the rectangles contained by the undivided line, and the several parts of the divided line. Let A and BC be two straight lines, and let BC be divided into any...
Σελίδα 112 - IF two triangles have two sides of the one equal to two sides of the...
Σελίδα 128 - To a given straight line to apply a parallelogram, which shall be equal to a given triangle, and have one of its angles equal to a given rectilineal angle.
Σελίδα 119 - If a side of any triangle be produced, the exterior angle is equal to the two interior and opposite angles; and the three interior angles of every triangle are together equal to two right angles.
Σελίδα 113 - ... equal angles in each ; then shall the other sides be equal, each to each ; and also the third angle of the one to the third angle of the other.
Σελίδα 273 - The opposite angles of any quadrilateral figure inscribed in a circle, are together equal to two right angles.
Σελίδα 281 - The angle in a semicircle is a right angle ; the angle in a segment greater than a semicircle is less than a right angle ; and the angle in a segment less than a semicircle is greater than a right angle.
Σελίδα 121 - THE straight lines which join the extremities of two equal and parallel straight lines, towards the same parts, are also themselves equal and parallel.