Arithmetic: In which the Principles of Operating by Numbers are Analytically Explained and Synthetically Applied : Illustrated by Copious ExamplesJ.W. Prentiss & Company, 1848 - 306 σελίδες |
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Σελίδα 44
... annexing a cipher repeats or increases it 10 times , which is 1 time too many : hence the rule , sub- tract it 1 time , & c . When the multiplier is 13 , 14 , & c . , why ? When When 21 , 31 , & c . , why ? 101 , 102 , & c . , why ? III ...
... annexing a cipher repeats or increases it 10 times , which is 1 time too many : hence the rule , sub- tract it 1 time , & c . When the multiplier is 13 , 14 , & c . , why ? When When 21 , 31 , & c . , why ? 101 , 102 , & c . , why ? III ...
Σελίδα 109
... annexing a cipher which , in effect , multi- plies them by 10 . Thus , 20 hundredths , ( % ) = and adding 15 hundredths , ( , ) we have 35 hundredths , ( 5. ) 2. From take . - 360 thousandths . 187 thousandths . 173 thousandths ...
... annexing a cipher which , in effect , multi- plies them by 10 . Thus , 20 hundredths , ( % ) = and adding 15 hundredths , ( , ) we have 35 hundredths , ( 5. ) 2. From take . - 360 thousandths . 187 thousandths . 173 thousandths ...
Σελίδα 113
... annexing ci- phers ; to tenths by annexing 1 cipher , since this is multiply- ing by 10 ; to hundredths by annexing two ciphers , & c . Thus , if 1 cipher be annexed to 25 it will be 25'0 , ( 250 tenths ; ) if 2 ciphers , it will be 25 ...
... annexing ci- phers ; to tenths by annexing 1 cipher , since this is multiply- ing by 10 ; to hundredths by annexing two ciphers , & c . Thus , if 1 cipher be annexed to 25 it will be 25'0 , ( 250 tenths ; ) if 2 ciphers , it will be 25 ...
Σελίδα 114
... annexing one cipher . 9'0236 9'0236 , already ten - thousandths . 17'0000 , annexing four ciphers . 175 All the numbers should be reduced to the denominator of the one having the greatest number of decimal places . EXAMPLES . 1. Reduce ...
... annexing one cipher . 9'0236 9'0236 , already ten - thousandths . 17'0000 , annexing four ciphers . 175 All the numbers should be reduced to the denominator of the one having the greatest number of decimal places . EXAMPLES . 1. Reduce ...
Σελίδα 115
... annexing two ciphers , before the division can begin . 66 ) 400 ( ' 0606+ , the Answer . 396 400 396 As there can be no tenths , a cipher must be placed in the quo- tient , in tenths ' place . NOTE . Cannot be reduced exactly ; for ...
... annexing two ciphers , before the division can begin . 66 ) 400 ( ' 0606+ , the Answer . 396 400 396 As there can be no tenths , a cipher must be placed in the quo- tient , in tenths ' place . NOTE . Cannot be reduced exactly ; for ...
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Συχνά εμφανιζόμενοι όροι και φράσεις
acres amount annexing apples arithmetic bought bushels called ciphers common fractions composite number compound interest Compound Numbers contained cord cost cube root cubic decimal fractions diameter divided dividend division dollars equal EXAMPLES FOR PRACTICE expressed factor farthings feet long figure frac gallons Give given number greatest common divisor Hence hogshead hundred hundredths improper fraction inches integers last term length measure merchant miles mills minuend mixed number months multiplicand multiply NOTE number of terms OPERATION oranges paid payment pence pieces pound present worth principal proper fraction proportion pupil quantity quarts Questions Questions.-T quotient rate per cent ratio receive Reduce remainder right hand rule shillings side sold solid feet SOLUTION square miles square root subtraction subtrahend tens tenths third thousandths tion units weight whole number write
Δημοφιλή αποσπάσματα
Σελίδα 146 - Thirty days hath September, April, June, and November ; All the rest have thirty-one, Except the second month alone, Which has but twenty-eight, in fine, Till leap year gives it twenty-nine.
Σελίδα 196 - What is the interest of $216'80, at 7 per cent., for 1 month ? for 2 months ? 3 mo. ? 4 mo. ? 5 mo. ? 6 mo. ? 7 mo. ? 8 mo. ? 9 mo.? 10 mo. ? 11 mo.
Σελίδα 287 - The first term, ratio , and number of terms given to find the sum of the series. 1. A lady bought 6 yards of silk, agreeing to pay 5 cents for the first yard, 15 for the second, and so on, increasing in a three fold proportion ; what did the whole cost ? SOLUTION.
Σελίδα 49 - The number to be divided is called the dividend. The number by which we divide is called the divisor. The number which shows how many times the divisor is contained in the dividend is called the quotient.
Σελίδα 236 - Reduce compound fractions to simple ones, and mixt numbers to improper fractions ; then multiply the numerators together for a new numerator, and the denominators for. a new denominator.
Σελίδα 60 - Multiply the last remainder by the first divisor, and to the product add the first remainder ; the sum will be the true remainder.
Σελίδα 55 - Multiply the integer of the quotient by the divisor, and to the product add the remainder, if any ; and the result will equal the dividend, if the work is right.
Σελίδα 147 - TABLE. 60 seconds (") - make - 1 minute, - marked - ' 60 minutes ----- 1 degree, - - - - - ° 30 degrees ,----- 1 sign, ------ s. 12 signs, or 360 degrees, - 1 circle of the zodiac. Note. Every circle, whether great or small, is divisible into 360 equal parts, called degrees. 71. Reduce 9s. 13° 25
Σελίδα 84 - To reduce a mixed number to an improper fraction, — RULE : Multiply the whole number by the denominator of the fraction, to the product add the numerator, and write the result over the denominator.
Σελίδα 83 - Fractions. Reduction of fractions is changing them from one form to another without altering their value. To reduce an improper fraction to a whole or mixed number. 1. In 4 halves (J) .of an apple how many whole apples?