Arithmetic: In which the Principles of Operating by Numbers are Analytically Explained and Synthetically Applied : Illustrated by Copious ExamplesJ.W. Prentiss & Company, 1848 - 306 σελίδες |
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Σελίδα 56
... length in the following manner . OPERATION . Div'r . Div'd . Quot . 21 ) 4478 ( 213 42 1st part . 27 21 2d part . 68 63 3d part . 5 Remainder . We say , 21 in 44 , ( hundreds , ) 2 ( hundred ) times , and write 2 on the right hand of ...
... length in the following manner . OPERATION . Div'r . Div'd . Quot . 21 ) 4478 ( 213 42 1st part . 27 21 2d part . 68 63 3d part . 5 Remainder . We say , 21 in 44 , ( hundreds , ) 2 ( hundred ) times , and write 2 on the right hand of ...
Σελίδα 69
... length and breadth of a rectangle given , to find the square contents . 1. How many square rods in a plat of ground 5 rods long and 3 rods wide ? D C B SOLUTION . A square rod is a square measuring 1 rod on each side , like one of those ...
... length and breadth of a rectangle given , to find the square contents . 1. How many square rods in a plat of ground 5 rods long and 3 rods wide ? D C B SOLUTION . A square rod is a square measuring 1 rod on each side , like one of those ...
Σελίδα 70
... length . 1. What is the length of a piece of ground 3 rods wide , and containing 15 square rods ? SOLUTION . -In this example we have 15 , the number of squares in several rows , ( see the diagram , problem I. , ) and 3 the number of ...
... length . 1. What is the length of a piece of ground 3 rods wide , and containing 15 square rods ? SOLUTION . -In this example we have 15 , the number of squares in several rows , ( see the diagram , problem I. , ) and 3 the number of ...
Σελίδα 71
... length , or really by the square contents of a portion of the ground 5 rods long and 1 rod wide . Ans . 3 rods . Hence , RULE . Divide the square contents by the length , and the quotient will be the width . EXAMPLES . 2. A piece of ...
... length , or really by the square contents of a portion of the ground 5 rods long and 1 rod wide . Ans . 3 rods . Hence , RULE . Divide the square contents by the length , and the quotient will be the width . EXAMPLES . 2. A piece of ...
Σελίδα 72
... length and breadth , and 1 foot high , to get the number of feet in the hight of the pile . Thus , 5X3 = 15 , and 60 ÷ 15≈4 feet in hight , Ans . Hence , RULE . Divide the solid contents by the product of the length mul tiplied by the ...
... length and breadth , and 1 foot high , to get the number of feet in the hight of the pile . Thus , 5X3 = 15 , and 60 ÷ 15≈4 feet in hight , Ans . Hence , RULE . Divide the solid contents by the product of the length mul tiplied by the ...
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acres amount annexing apples arithmetic bought bushels called ciphers common fractions composite number compound interest Compound Numbers contained cord cost cube root cubic decimal fractions diameter divided dividend division dollars equal EXAMPLES FOR PRACTICE expressed factor farthings feet long figure frac gallons Give given number greatest common divisor Hence hogshead hundred hundredths improper fraction inches integers last term length measure merchant miles mills minuend mixed number months multiplicand multiply NOTE number of terms OPERATION oranges paid payment pence pieces pound present worth principal proper fraction proportion pupil quantity quarts Questions Questions.-T quotient rate per cent ratio receive Reduce remainder right hand rule shillings side sold solid feet SOLUTION square miles square root subtraction subtrahend tens tenths third thousandths tion units weight whole number write
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Σελίδα 146 - Thirty days hath September, April, June, and November ; All the rest have thirty-one, Except the second month alone, Which has but twenty-eight, in fine, Till leap year gives it twenty-nine.
Σελίδα 196 - What is the interest of $216'80, at 7 per cent., for 1 month ? for 2 months ? 3 mo. ? 4 mo. ? 5 mo. ? 6 mo. ? 7 mo. ? 8 mo. ? 9 mo.? 10 mo. ? 11 mo.
Σελίδα 287 - The first term, ratio , and number of terms given to find the sum of the series. 1. A lady bought 6 yards of silk, agreeing to pay 5 cents for the first yard, 15 for the second, and so on, increasing in a three fold proportion ; what did the whole cost ? SOLUTION.
Σελίδα 49 - The number to be divided is called the dividend. The number by which we divide is called the divisor. The number which shows how many times the divisor is contained in the dividend is called the quotient.
Σελίδα 236 - Reduce compound fractions to simple ones, and mixt numbers to improper fractions ; then multiply the numerators together for a new numerator, and the denominators for. a new denominator.
Σελίδα 60 - Multiply the last remainder by the first divisor, and to the product add the first remainder ; the sum will be the true remainder.
Σελίδα 55 - Multiply the integer of the quotient by the divisor, and to the product add the remainder, if any ; and the result will equal the dividend, if the work is right.
Σελίδα 147 - TABLE. 60 seconds (") - make - 1 minute, - marked - ' 60 minutes ----- 1 degree, - - - - - ° 30 degrees ,----- 1 sign, ------ s. 12 signs, or 360 degrees, - 1 circle of the zodiac. Note. Every circle, whether great or small, is divisible into 360 equal parts, called degrees. 71. Reduce 9s. 13° 25
Σελίδα 84 - To reduce a mixed number to an improper fraction, — RULE : Multiply the whole number by the denominator of the fraction, to the product add the numerator, and write the result over the denominator.
Σελίδα 83 - Fractions. Reduction of fractions is changing them from one form to another without altering their value. To reduce an improper fraction to a whole or mixed number. 1. In 4 halves (J) .of an apple how many whole apples?