Plane and Solid Geometry |
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Αποτελέσματα 1 - 5 από τα 36.
Σελίδα 11
The angles included by the adjacent sides are the angles of the polygon , and
their vertices are the vertices of the polygon . An exterior angle is formed by a
side and the prolongation of an adjacent one . A diagonal is a straight line joining
the ...
The angles included by the adjacent sides are the angles of the polygon , and
their vertices are the vertices of the polygon . An exterior angle is formed by a
side and the prolongation of an adjacent one . A diagonal is a straight line joining
the ...
Σελίδα 14
Arthur Schultze, Frank Louis Sevenoak. PROPOSITION III . THEOREM 72 . Two
triangles are equal if two sides and the included angle of the one are equal
respectively to two sides and the included angle of the other ( s . a . s . = s . a . s . )
.
Arthur Schultze, Frank Louis Sevenoak. PROPOSITION III . THEOREM 72 . Two
triangles are equal if two sides and the included angle of the one are equal
respectively to two sides and the included angle of the other ( s . a . s . = s . a . s . )
.
Σελίδα 31
If a quadrilateral has two pairs of equal adjacent sides , the angles included by
the unequal sides are equal . Ex . 120 . The medians to the arms of an isosceles
triangle are equal . Ex . 121 . If the opposite sides of a quadrilateral are equal ,
the ...
If a quadrilateral has two pairs of equal adjacent sides , the angles included by
the unequal sides are equal . Ex . 120 . The medians to the arms of an isosceles
triangle are equal . Ex . 121 . If the opposite sides of a quadrilateral are equal ,
the ...
Σελίδα 39
Ex . 158 . Given a polygon of five sides ( pentagon ) ABCDE . Required a
pentagon having four of its sides equal respectively to AB , BC , CD , and DE ,
and the included angles equal to A B , C , and D . A PROPOSITION XXIV .
PROBLEM 118 .
Ex . 158 . Given a polygon of five sides ( pentagon ) ABCDE . Required a
pentagon having four of its sides equal respectively to AB , BC , CD , and DE ,
and the included angles equal to A B , C , and D . A PROPOSITION XXIV .
PROBLEM 118 .
Σελίδα 45
If two triangles have two sides of the one equal respectively to two sides of the
other , but the included angle of the first greater than the included angle of the
second , then the third side of the first is greater than the third side of the second .
If two triangles have two sides of the one equal respectively to two sides of the
other , but the included angle of the first greater than the included angle of the
second , then the third side of the first is greater than the third side of the second .
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Συχνά εμφανιζόμενοι όροι και φράσεις
ABCD altitude angle angles are equal base bisect bisector called chord circle circumference circumscribed coincide common cone construct contains corresponding cylinder diagonals diameter diedral angles difference distance divide draw drawn equal equidistant equivalent exterior angle faces figure Find formed four frustum geometrical given circle given line given point greater Hence homologous hypotenuse inches included inscribed intersecting isosceles triangle lateral edges length less limit line joining measured median meet midpoints opposite sides parallel parallel lines parallelogram passing perimeter perpendicular plane polyedron polygon prism PROBLEM Proof PROPOSITION prove pyramid quadrilateral radii radius ratio rectangle regular polygon respectively right angles right triangle School segments sides similar sphere spherical triangle square straight line surface tangent THEOREM third transform triangle triangle are equal vertex vertices
Δημοφιλή αποσπάσματα
Σελίδα 45 - If two triangles have two sides of one equal respectively to two sides of the other, but the included angle of the first triangle greater than the included angle of the second, then the third side of the first is greater than the third side of the second.
Σελίδα 119 - In any proportion, the product of the means is equal to the product of the extremes.
Σελίδα 180 - The areas of two triangles which have an angle of the one equal to an angle of the other are to each other as the products of the sides including the equal angles. A D A' Hyp. In triangles ABC and A'B'C', To prove AABC A A'B'C' A'B' x A'C ' Proof. Draw the altitudes BD and B'D'.
Σελίδα 31 - The median to the base of an isosceles triangle is perpendicular to the base.
Σελίδα 305 - A cylinder is a solid bounded by a cylindrical surface and two parallel planes; the bases of a cylinder are the parallel planes; and the lateral surface is the cylindrical surface.
Σελίδα 337 - A spherical polygon is a portion of the surface of a sphere bounded by three or more arcs of great circles. The bounding arcs are the sides of the polygon ; the...
Σελίδα 250 - A straight line perpendicular to one of two parallel planes is perpendicular to the other also.
Σελίδα 297 - A truncated triangular prism is equivalent to the sum of three pyramids whose common base is the base of the prism, and whose vertices are the three vertices of the inclined section.
Σελίδα 105 - I. When the given point, A, is in the circumference. HINT. — What is the angle formed by a radius and a tangent at its extremity ? II. When the given point, A, is without the circle. \ Construction. Join A, and 0 the center of the given circle. On OA as a diameter, construct a circumference, intersecting the given circumference in B and C.
Σελίδα 276 - An oblique prism is equivalent to a right prism whose base is a right section of the oblique prism, and whose altitude is equal to a lateral edge of the oblique prism. Hyp. GM is a right section of oblique prism AD', and OM ' a right prism whose altitude is equal to a lateral edge of AD'. To prove AD' =s= GM'. Proof. The lateral edges of GM
Πληροφορίες βιβλιογραφίας
| Τίτλος | Plane and Solid Geometry Plane and Solid Geometry, Frank Louis Sevenoak |
| Συγγραφείς | Arthur Schultze, Frank Louis Sevenoak |
| Εκδότης | Macmillan, 1902 |
| Μέγεθος | 370 σελίδες |
| Εξαγωγή αναφοράς | BiBTeX EndNote RefMan |