 | John Caldwell Colt - 1846 - 204 σελίδες
...thick, 12 inches wide, and 18 feet long, board measure ? 12X2^X18=540-7- 12=45 feet. Ans. NOTE.— To find the area of a square multiply the length by the breadth. How many square feet are contained in the plaster or wall of a room which measures 20 feet by 35 feet... | |
 | George Nixon Comer - 1847 - 124 σελίδες
...in board measure of a plank 1J inch thick, 15 inches wide and 20 feet long. 1JX 15X20 = 450 -7-12 = Feet 37, in. 6. Ans. To find the area of a square,...multiplied by feet produce feet ; feet multiplied by inches produce inches ; inches multiplied by inches produce twelfths of inches. 103 Required the number of... | |
 | George Nixon Comer - 1850 - 126 σελίδες
...in board measure of a plank 1J inch thick, 15 inches wide and 20 feet long. 1 JX 15X20 = 450 -H2 = Feet 37, in. 6. Ans. To find the area of a square,...in a parcel of land which measures 20 by 69 feet. t 20X69 = Ans. 1380 square feet. Feet multiplied by feet produce feet ; feet multiplied by inches produce... | |
 | Richard Nelson - 1867 - 304 σελίδες
...center to any point in the circumference. NELSON'S COMMON-SCHOOL ARITHMETIC. XXXVIII. MENSURATION. 315. To find the area of a square, multiply the length by the breadth. 1. Let oue side of the annexed parallelogram be 3, and the other 4, then the area will be 3X4=12. 2.... | |
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Feet 37, in. 6. Ans. To find the area of a square, multiply the length by the breadth. Required the number of square feet in a parcel of land which measures 20 by 69 feet. 20X69 = Ans. 1380 square feet. Feet multiplied by feet produce feet ; feet multiplied... 