Elements of GeometryHilliard and Metcalf, 1825 - 224 σελίδες |
Αναζήτηση στο βιβλίο
Αποτελέσματα 1 - 5 από τα 82.
Σελίδα xiv
... Hence the product of two lines A and D , which is called also their rectangle , is nothing else than the number of linear units contained in A multiplied by the number of linear units con- tained in B ; and we can easily conceive this ...
... Hence the product of two lines A and D , which is called also their rectangle , is nothing else than the number of linear units contained in A multiplied by the number of linear units con- tained in B ; and we can easily conceive this ...
Σελίδα 4
... hence ACK KCB . ACK > ACD , KCB < BCD ; ACD BCD ; ACK > KCB . and the line GH cannot fall upon a line CK different from CD ; consequently it falls upon CD , and the angle EGH upon ACD , and EGH is equal to ACD ; therefore all right ...
... hence ACK KCB . ACK > ACD , KCB < BCD ; ACD BCD ; ACK > KCB . and the line GH cannot fall upon a line CK different from CD ; consequently it falls upon CD , and the angle EGH upon ACD , and EGH is equal to ACD ; therefore all right ...
Σελίδα 10
... Hence a straight line drawn from the vertex of an isosceles triangle , to the middle of the base , is perpendicular to that base , and divides the ver- tical angle into two equal parts . In a triangle that is not isosceles , any one of ...
... Hence a straight line drawn from the vertex of an isosceles triangle , to the middle of the base , is perpendicular to that base , and divides the ver- tical angle into two equal parts . In a triangle that is not isosceles , any one of ...
Σελίδα 11
... hence it would follow that two straight lines ACF , ABF , might be drawn between the same two points A and F , which is impossible ( 25 ) ; it is then equally impossible to draw two perpendiculars from the same point to the same ...
... hence it would follow that two straight lines ACF , ABF , might be drawn between the same two points A and F , which is impossible ( 25 ) ; it is then equally impossible to draw two perpendiculars from the same point to the same ...
Σελίδα 20
... Hence two parallels AB , CD , comprehended between two other parallels AD , BC , are equal . THEOREM . 86. If , in a quadrilateral ABCD ( fig . 44 ) , the opposite sides are equal , namely , AB = CD , and AD CB , the equal sides will be ...
... Hence two parallels AB , CD , comprehended between two other parallels AD , BC , are equal . THEOREM . 86. If , in a quadrilateral ABCD ( fig . 44 ) , the opposite sides are equal , namely , AB = CD , and AD CB , the equal sides will be ...
Άλλες εκδόσεις - Προβολή όλων
Συχνά εμφανιζόμενοι όροι και φράσεις
ABC fig adjacent angles altitude angle ACB angle BAD angles equal base ABCD bisect centre chord circ circular sector circumference circumscribed common cone consequently construction convex surface Corollary cube cylinder Demonstration diagonals diameter draw drawn equal and parallel equiangular equilateral equivalent faces figure four right angles frustum Geom gles greater hence homologous sides hypothenuse inclination inscribed circle intersection isosceles join less let fall line AC manner mean proportional measure the half meet multiplied number of sides oblique lines opposite parallelogram parallelopiped perimeter perpendicular plane MN polyedron prism proposition quadrilateral radii radius ratio rectangle regular polygon right angles right-angled triangle Scholium segment semicircumference side BC similar solid angle sphere spherical polygons spherical triangle square described straight line tangent THEOREM three plane angles triangle ABC triangular prism triangular pyramids vertex vertices whence
Δημοφιλή αποσπάσματα
Σελίδα 65 - The square of the hypothenuse is equal to the sum of the squares of the other two sides ; as, 5033 402+302.
Σελίδα 21 - If two triangles have the three sides of the one equal to the three sides of the other, each to each, the triangles are congruent.
Σελίδα ii - Co. of the said district, have deposited in this office the title of a book, the right whereof they claim as proprietors, in the words following, to wit : " Tadeuskund, the Last King of the Lenape. An Historical Tale." In conformity to the Act of the Congress of the United States...
Σελίδα 63 - The areas of two triangles which have an angle of the one equal to an angle of the other are to each other as the products of the sides including the equal angles. A D A' Hyp. In triangles ABC and A'B'C', To prove AABC A A'B'C' A'B' x A'C ' Proof. Draw the altitudes BD and B'D'.
Σελίδα 22 - CIRCLE is a plane figure bounded by a curved line, all the points of which are equally distant from a point within called the centre; as the figure ADB E.
Σελίδα ii - States entitled an act for the encouragement of learning hy securing the copies of maps, charts and books to the author., and proprietors of such copies during the times therein mentioned, and also to an act entitled an act supplementary to an act, entitled an act for the encouragement of learning by securing the copies of maps, charts and books to the authors and proprietors of such copies during the times therein mentioned and extending the benefits thereof to the arts of designing, engraving and...
Σελίδα 80 - The perimeters of two regular polygons of the same number of sides, are to each other as their homologous sides, and their areas are to each other as the squares of those sides (Prop.
Σελίδα 164 - If two triangles have two sides and the inchtded angle of the one respectively equal to two sides and the included angle of the other, the two triangles are equal in all respects.
Σελίδα 24 - In the same circle, or in equal circles, equal arcs are subtended by equal chords ; and, conversely, equal chords subtend equal arcs.
Σελίδα 153 - XVII.) ; hence two similar pyramids are to each other as the cubes of their homologous sides.