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" To find the area of a triangle. Multiply the base by the perpendicular height, and... "
A treatise on arithmetic. [With] Key - Σελίδα 319
των James Thomson - 1880
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The principles of architecture, Τόμος 1

Peter Nicholson - 1809 - 426 σελίδες
...is the' area of a rhomboides ABCD, whose length AB is l6f. 3i. and the height DE 5f. 6i. ? PROBLEM II. To find the area of a triangle. Multiply the base by the perpendicular height, and half the product will be the area. EXAMPLE 1. I What is the area of a triatgk ABC, the...

The Operative Mechanic, and British Machinist: Being a Practical Display of ...

John Nicholson (civil engineer.) - 1825 - 1008 σελίδες
...the area of a rhombus, whose length is 6 chains, and perpendicular height 5. - 5 5 Ansr. 30 Proli. 2. To find the Area of a Triangle. /.'•'/..• ]. Multiply the base by the perpendicular height, and half the product will be the area. Rule 2. When the three sides only are given : Add the...

A Popular Course of Pure and Mixed Mathematics ...: With Tables of ...

Peter Nicholson - 1825 - 1046 σελίδες
...16 3 1625 5 6 55 D С 9 81 8125 8125 f. 89.375 Л 89 4 6 f. i ii Ans. 89 ft. 4 in. 6 parts. Prob. 2. To find the area of a triangle. Multiply the base by the perpendicular height, and half the product will be the area. Ex. What is the area of a triangle ABC, the base AB...

The Arithmetical Manual

Samuel Read Hall - 1832 - 294 σελίδες
...breadth, or height, and the product will be the area • as above, 8 ft. X 3=24, the area of ABCD. To find the area of a Triangle, — Multiply the base by the perpendicular height, and take half the product for the area. The reason for the above rule will be evident from...

A Practical and Theoretical System of Arithmetic...: Also, a Treatise on ...

George Willson - 1836 - 202 σελίδες
...of a rectangle of equal sides. Consequently, To find the area of a right-angled triangle : RULE. — Multiply the base by the perpendicular, and take half the product : or, multiply one into half the other, and the result is the area. If the triangle be not right-angled, that is, ha-ve...

Treatise on Arithmetic, in Theory and Practice: With an Appendix, Containing ...

James Thomson (LL.D.) - 1837 - 296 σελίδες
...side of a square table be 3 feet, 10 inches, what is its content? Aiuw. 14f. 8' 4*. RULE II. To Jind the area of a triangle : Multiply the base by the...other. Exam. 4. Required the area of the triangle ACD (see the diagram page 265) whose base CD is 15 feet 4 inches, and its perpendicular AE, 8 feet 7 inches....

A Practical and Theoretical System of Arithmetic: Containing a New System of ...

George Willson - 1838 - 194 σελίδες
...of a rectangle of equal sides. Consequently, To find the area of a right-angled triangle : RULE. — Multiply the base by the perpendicular, and take half the product ; or, multiply one into half the other, and the result is the area. If the triangle be not right-angled, that is, ha\e...

The parent's guide to a liberal ... education; containing a selection of ...

Robert Simson (master of Colebrooke house acad, Islington.) - 1838 - 206 σελίδες
...the area. Let the sides of a rectangle be 12 and 9, what isits area? 12 X 9=108 the area. How do you find the area of a triangle ? Multiply the base by the perpendicular height, and half the product will be the area. Find the area of a triangle, of which the base is 115,...

Principles of Architecture: Comprising Fundamental Rules of the Art, with ...

Peter Nicholson, Joseph Gwilt - 1848 - 750 σελίδες
...16 3 16-25 56 56 5-5 8125 8125 Ans. 89 4 6 89 4 6 f. S'J-375 f. i ii f. i ii PROBLEM II. PLATE 50. To find the area of a triangle. Multiply the base by the perpendicular height, and half the product will be the area. EXAMPLE I. What is the area of a triangle ABC, the base...

The Teacher's Aid, Containing the Solution of a Variety of the Most ...

Goodwin Mitchell - 1849 - 224 σελίδες
...length by the breadth, or multiply the side and end together, and the product will be the area. (22) To find the area of a triangle : Multiply the base by the perpendicular height of the triangle, and half the product will be the area ; or multiply the perpendicular by half...




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