 | Bézout - 1825 - 258 σελίδες
...add these products, and we have, for the square, the number 2916, which, as we see, is composed of the square of the tens, plus twice the product of the tens by the units, plus the square of the units of the number 54. 134. What we have, observed being an immediate... | |
 | William Smyth - 1830 - 278 σελίδες
...Designating the tens by a and the units by b, we have a+6 = 47, and squaring both sides o2-|- 2 06 + 62=2209. Thus the square of a number, consisting of units and...the tens (a2) = 1600 twice the tens by the units (2 ab) = 560 the square if the units (62) = 49 2209 Considering then the proposed number 6084 as composed... | |
 | William Smyth - 1833 - 288 σελίδες
...the tens by a and the units by 6, we have a -f-6 = 47, and squaring both sides a2 -j- 2 ab + b2 =^ 2209. Thus the square of a number, consisting of units...square of the tens, plus twice the product of the tens multiplicd by the units, plus the square of the units. Thus in 2209, the square of 47, we have the... | |
 | Charles Davies - 1835 - 378 σελίδες
...64 and (a+i)3= (64)3 Which proves that the square of a number composed of tens and units contains, the square of the tens plus twice the product of the tens by the units, plus the square of the units. 117. If now, we make the units 1, 2, 3, 4, &c., tens, by... | |
 | William Smyth - 1836 - 288 σελίδες
...Designating the tens by a and the units by b, we have a + b =47, and squaring both sides a2 -|- 2 a6 -|- 62 = 2209. Thus the square of a number, consisting of units...the tens multiplied by the units, plus the square vf the units. Thus in 2209, the square of 47, we have the square of the tens (a2) = 1600 twice the... | |
 | 1838 - 372 σελίδες
.... . aa+2a*+i3 =4096. Which proves that the square of a number composed of tens and units contains, the square of the tens plus twice the product of the tens by the units, plus the square of the units. 117. If now, we make the units 1, 2, 3, 4, &c., tens, by... | |
 | Charles Davies - 1839 - 272 σελίδες
...shall have a+b =64, and Which proves that the square of a number composed of tens and units, contains the square of the tens plus twice the product of the tens by the units, plus the square of the units. 94. If, now, we make the units 1,2, 3, 4, &c, tens, or... | |
 | Great Britain. Poor Law Commissioners - 1841 - 450 σελίδες
...square contained in the first period. The square of this being subtracted, the remainder contains twice the tens, multiplied by the units, plus the square of the units. The units therefore may be found by dividing the remainder by 2 a. The units figure 4, being added... | |
 | Charles Davies - 1842 - 368 σελίδες
...and (a+i) 3 =(64) 3 , Which proves that the square of a number composed of tens and units contains, the square of the tens plus twice the product of the tens by the units, plus the square of ihe units. 117. If now, we make the units 1, 2, 3, 4, &c., tens, by... | |
 | Charles Davies - 1842 - 284 σελίδες
...(a+6)2=(64)2; or a2 + Which proves that the square of a number composed of tens and units, contains the square of the tens plus twice the product of the tens by the units, plus the square of the units. 94. If, now, we make the units 1,2, 3, 4, &c, tens, or... | |
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Which proves that the square of a number composed of tens and units contains, the square of the tens plus twice the product of the tens by the units, plus the square of the units. 
