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13. If x1+ 2ax3y — ay3 = 0, shew that dy

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when x=0 and y = 0.

= 0, or ±√2,

dx

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14. If x2- ay3+2axy2+3ax3y=0, shew that

or 3, when x=0 and y = 0.

y=0.

15. If ax3+x3y — ay3 = 0, shew that dy

— :

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= dx

16. If x2y2 = (a2 — y3) (b+ y)2, shew that

when x= 0 and y=-b.

3

dy

dx

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2 (y2+ x2 - 2x)2,

17. If (y2 — x2) (x − 1) ( x − 2)

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=

find

Results

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dy

dx

when x and y vanish, and when x=1, y=1.

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16

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u2 + x2 + y2+ z2 = c2,

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7. Given y3 + x3 — 3axy = 0, shew that

dy

find

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9. If y=(x, y, u) and f (x, y, u) = 0, find

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du

11. If u = a2 + √(sec xy), find da (1) when x and y are

dx'

independent, (2) when x+y=a.

12. If a+√(sec xy) = 0, find

dy

dx

dy y√(sec xy) tan xy + 2a yx2-1log a Result

=

dx x√(sec xy) tan xy+2a**x log a logx

dy

13. If x+2ax3y - ay3 = 0, shew that

= 0, or ±√√2,

dx

when x= 0 and y = 0.

14. If x*— ay3+2axy®+ 3axy=0, shew that dy

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16. If x3y2 = (a2 — y2) (b+ y)2, shew that

when x=0 and y =—b.

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dx

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dy

b

= +

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=

= 2 (y2+ x2 — 2x)3,

18.

find dy when a and y vanish, and when x=1, y=1.

dx

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If y* — yo + 3xy — 2x2 = 0, find dy when x = 0.

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dx

u3 + x2 + y2+z2 = c2,

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CHAPTER XII.

CHANGE OF THE INDEPENDENT VARIABLE.

196. In Art. 60 we have proved the equation

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and we now proceed to some extensions of these formulæ.

Given x and y, both functions of a third variable z, it is required to express the successive differential coefficients of y with respect to x, in terms of those of y and x with respect to z.

We have

dy_dy dz

=

dx dz dx

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by (2),

dz

by (1).

dx

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the independent variable is z.

197. Suppose in the preceding article we put z=y.

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