EXAMPLE 3.. In a survey, represented Fig. 81, the corner at A was inaccessible, occasioned by the overflowing of water, but being a tree, it can be seen from the adjacent corners B and L. I therefore set my instrument at B and took the bearing to A, which I reversed, and set in my field. book as the first bearing. I then proceeded to take the bearings and distances of the several sides to L; and at L, I took the bearing of the side LA. The field-notes being as follow, the length of the sides AB and LA, and the area are required. By taking the difference of latitude and departure for each of the sides BC, CD, DE, EF, FG, GH, HI, IK, and KL, and balancing, we shall have the difference of latitude and departure of LB, with which its bearing and distance may be found as in the last example. R To tang. of the bearing of LB, S. 78° 49′ W. 10.70110 As rad. 10.00000 Is to sec. of the bearing of LB 78° 49′ 10.71231 So is diff. of lat. do. 5.73 0.75815 11.47046 Now, having the bearings of the lines AB, LB and AL, the angles contained by them may be found by the rules given page 82. Then in the triangle ALB, all the angles and one side LB will be given to find the other ' PRACTICAL EXAMPLES, To be calculated by either of the preceding Rules. 1. Given the boundaries of a tract of land as follow, viz. 1st. S 35° W, 11.20 ch. 2nd. N 45° W, 24.86 ch. 3rd. N 15° E, 10.80 ch. 4th. S 77° E, 16 ch. 5th. N 87°; E, 21.50 ch. 6th. S 60° E, 14.80 ch. 7th. South, 10.91 ch. 8th. N 85 W, 29.28 ch. to the place of beginning; required the area. Ans. 85 A. 3 R. 17 P. 2. Given the boundaries of a tract of land as follow: viz. 1st. N 19° E, 27 ch. 2nd. S 77° E, 22.75 ch. 3rd. S 27° E, 28.75 ch. 4th. S 52° W, 14.50 ch. 5th. S 15° E, 19 ch. 6th. West, 17.72 ch. 7th. N 36° W, 11.75 ch. 8th. North, 16.07 ch. 9th. N 62° W, 14.88 ch. to the place of beginning; required the area. Ans. 152 A. 2 R. 6 P. 3. Required the area of a tract of land bounded as follows: 1st. S 62° W. 7.57 ch. 2nd. N 43° W, 5.89 ch. 3rd. North, 5.82 ch. 4th. N 33° W, 8.83 ch. 5th. N 48° E, 4.81 ch. 6th. N 12° E, 4.66 ch. 7th. N 62° E, 5.27 ch. 8th. S 6° E, 5.60 ch. 9th. S 40° 10th. East, 6.54 ch. 11th. North, 5.52 ch. 68° E, 3.10 ch. 13th. S 30° E, 7.90 ch. E, 5.87 ch. 12th. N. 14th. S 23° W, 8.80 ch. 15th. S 31° E, 6.42 ch. 16th. S 50° W, 8.40 ch. 17th. $44 W, 6.85 ch. to the place of beginning. *44, 7 Ans. 44 A. 2 R. 18 P. 4. Given the following field-notes to find the area of the survey; also the bearing and distance of the 3rd side, which were omitted to be taken on account of obstacles |