Daboll's Complete Schoolmaster's Assistant Being a Plain Comprehensive System of Practical ArithmeticBolles and Williams, 1843 - 240 σελίδες |
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Σελίδα 3
... leaving the pupil to solve without proper and concise rules nearly all questions in Arithmetic ; and thus in endeavoring to correct one error , have , as regards Common Schools , run into another as great . A small introduction to the ...
... leaving the pupil to solve without proper and concise rules nearly all questions in Arithmetic ; and thus in endeavoring to correct one error , have , as regards Common Schools , run into another as great . A small introduction to the ...
Σελίδα 8
... leave 6 5 from 12 leave 7 5 from 13 leave 8 5 from 14 leave 9 3 from 3 from 3 leave 0 3 from 4 leave 1 5 leave 2 6 leave 3 3 from 7 leave 4 3 from 8 leave 5 3 from 9 leave 6 3 from 10 leave 7 3 from 11 leave 8 3 from 12 leave 9 6 from 6 ...
... leave 6 5 from 12 leave 7 5 from 13 leave 8 5 from 14 leave 9 3 from 3 from 3 leave 0 3 from 4 leave 1 5 leave 2 6 leave 3 3 from 7 leave 4 3 from 8 leave 5 3 from 9 leave 6 3 from 10 leave 7 3 from 11 leave 8 3 from 12 leave 9 6 from 6 ...
Σελίδα 26
... . 4. Why ? Because 6 taken from 10 leave 4 , or 4 added to 6 make 10 . 2. A boy having 9 cents paid 5 for apples , and lost the remainder , how many did he lose ? 3. James had 12 apples and John 7 , how 26 SUBTRACTION .
... . 4. Why ? Because 6 taken from 10 leave 4 , or 4 added to 6 make 10 . 2. A boy having 9 cents paid 5 for apples , and lost the remainder , how many did he lose ? 3. James had 12 apples and John 7 , how 26 SUBTRACTION .
Σελίδα 28
... leave 4 units ; and 4 tens from 5 tens leave 1 ten ; and 6 hundreds from 8 hundreds leave 2 hundreds , and nothing from 1 thousand leaves 1 thousand ; and the answer is 1214 . 2. Subtract 528 from 873 and how many remains ? Greater num ...
... leave 4 units ; and 4 tens from 5 tens leave 1 ten ; and 6 hundreds from 8 hundreds leave 2 hundreds , and nothing from 1 thousand leaves 1 thousand ; and the answer is 1214 . 2. Subtract 528 from 873 and how many remains ? Greater num ...
Σελίδα 29
... leaves 4 , the same as above . Hence is derived the Rule . " When the lower figure is greater than the figure above it add 10 to the upper figure , " & c . Proof . The remainder and less number added together are equal to the greater ...
... leaves 4 , the same as above . Hence is derived the Rule . " When the lower figure is greater than the figure above it add 10 to the upper figure , " & c . Proof . The remainder and less number added together are equal to the greater ...
Άλλες εκδόσεις - Προβολή όλων
Complete Schoolmaster's Assistant: Being a Plain Comprehensive System of ... Nathan Daboll Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2016 |
Συχνά εμφανιζόμενοι όροι και φράσεις
2qrs 3qrs acres 3 roods annex annuity answer Arithmetic barrels breadth broadcloth bushels called cent per annum ciphers circumference common denominator common difference common multiple compound interest contained cords cost cube root diameter divi dividend divisor dollars dols equal EXAMPLES farthings Federal money find the amount Find the value frustrum gain gallons given number given sum greatest common divisor hogshead hundred improper fraction last term least common multiple leave length lowest terms merchant bought miles mills mixed number months multiplicand Multiply Note number of terms payment pence pint pound present worth principal PROB proportion quantity quarts quotient figure rate per cent ratio Reduce remainder right hand Rule of Three separatrix shillings sold solid contents square rods square root subtract subtrahend sugar tare tens thousand units VULGAR FRACTIONS weight whole number wine yards of cloth
Δημοφιλή αποσπάσματα
Σελίδα 195 - Find the first figure of the root by trial, and subtract its power from the left hand period of the given number. 3. To the remainder bring down the first figure in the next period, and call it the dividend. 4. Involve the root to the next inferior power to that which is given, and multiply it by the number denoting the given power, for a divisor.
Σελίδα 167 - Multiply all the numerators together for a new numerator, and all the denominators for a new denominator; and they will form the fraction required.
Σελίδα 183 - ... subtract it therefrom, and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found, on the left hand of the dividend for a divisor. 4. Seek how often the divisor is contained...
Σελίδα 106 - Let the farthings in the given pence and farthings possess the second and third places ; observing to increase the second place or place of hundredths, by 6 if the shillings be odd ; and the third place by 1 "when the farthings exceed 12, and by 2 when they exceed 36. EXAMPLES. 1. Find the decimal of 7s. 9fd. by inspection. ,3 =4 6s. 5 for the odd shillings. 39=the farthings in 9|d. 2 for the excess of 36. £. ,391=dechnal required'.
Σελίδα 90 - To reduce an improper fraction to a whole or mixed number. RULE. Divide the numerator by the denominator, and the quotient will be the whole or mixed number sought.
Σελίδα 233 - To measure a Parallelogram, or long square. RULE. Multiply the length by the breadth, and the product will be the area or superficial content.
Σελίδα 44 - If any partial dividend will not contain the divisor, place a cipher in the quotient, and bring down the next figure of the dividend, and divide as before.
Σελίδα 126 - ... multiply the second and third terms together, and divide the product by the first for the answer, which will always be of the same denomination as the third term.
Σελίδα 119 - Then multiply the second and third terms together, and divide the product by the first term: the quotient will be the fourth term, or answer.
Σελίδα 205 - ... the terms, RULE. Multiply the sum of the extremes by the number of terms, and half the product will be the sum of the terms.