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Case 4th.-When the price is an aliquot part of a shilling. Consider the quantity as pounds or shillings, which ever, will most readily answer the question, and divide it by the denominators of the several aliquot parts of which the given alie, quot part is composed.

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CASE 5th–When the price is 2s. or an aliquot part thereof double the units place for shillings, the other figures will give the pounds of the answer when the price is 2s. When an aliquot find the price at 2s. which divide by the denominator of the given aliquot part, - * 25. When the price is 10d. annex a cipher to the given number, and divide by 12 and 30, or without annexing the cipherdivide 2 and fz.” 26. When the price is lld, multiply by ll as taught in Multiplication: and divide by 12 and 20. 31. 14 is an aliquot part of a pound therefore divide by 16 and 12. 34.2% is an aliquot part of a pound therefore divide by 12 and 8. 37. & 38. For 34 or 33 take an 80th of a;6 and an aliquot part thereof. 42. For 5 divide 12 and 4. . 51. For 73 divide by 8 and 4. * * 32. From 2d. an 120th part of a £ subtract id.-# of 2d. 38, 34 is also an aliquot part of a 4 therefore divide by 8 and 3,

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Case 6th.-When the complement of 2s. Find the price at 2s. as before from which subtract the amount at the difference between the given price and 2s.

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70. 473 at 1 6 71. 1731 at 1 8, 72.4717 at 1 10 73. 695 at 1 9, 74. 1327 at 1 11+ 75.8396 at I 11 76. 1321 at 1 10+ 77, 4371 at 1 9 78. 1733 at 1 8 CAss 7th.-When the prices are even shillings. Multiply by half the number of shillings, doubling the first figure of the product for the shillings of the answer, the remainder of the product will be pounds. . And instead of placing half the given number of shillings under the given quantity, a line will be saved by placing this number in the margin as a fraction with 10 for a denominator, and by multiplying by this numerator and doubling the units figure the operation will be exactly the same,

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79. 1493 at 4s. 80. 1315 at 6s, 81. 4314 at 8s. 82. 1733 at 12s, 83. 4391 at 14s, 84. 3715 at 16s. 85. 1347 at 18s, 86. 1 141 at 22s. 87. 1471 at 6s. 88. 4735 at 22s. 89. 1342 at 24s. 90. 3174 at 12s. Case 8th—When the prices are odd shillings. Find the amount at the highest number of even slillings therein as before directed, and for the odd shilling add oth

part of the given quantity considered as pounds, the sum will be the answer.

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Consider the given quantity as pounds, which divide by the denominator of the given aliquot part.

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s. d. s. d. s. d 100. 496 at 10 0 101. 843 at 6 8 102. 475 at 50 103. 1231 at. 4 0 104. 4731 at 34 105. 874 at 2 6 106. 347 at 2 0 107. 869 at 1 8 108. 1711 at 1 4 109. 893 at I 3. 110. 1431 at 1 0 111. 893 at 10 112. 1321 at 8 113. 896 at 74, 114, 815 at 6 115. 863 at 8 116.. 943 at 4, 117. 1321 at 34 Case 10th–When the price is the complement of a pound. Subtract the given price from a pound, and divide the quantity by the denominator of such aliquot part of a pound as this remainder may be of the same, which subtract from the given

quantity, considered as pounds. '
* (Brampscă.

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s, d. w s. d. s. d. 118. 2731 at 15 0 119. 873 at 16 8 120. 1342 at 13 4 121. 1431 at 16 0 122. 1324 at 17 6 123. 1733 at 18 4 124. 1325 at 18 8 125. 1741 at 18 9 126. 1415 at 19 0 127. 2133 at 19 2 128. 1873 at 194 129. 1432 at 1984 130. 495 at 19 6 131. 1324 at 19 8 132. 839 at 194} 133. 4311 at 19 9 134, 1845 at 19 to 135. 8641 at 19 ió 136. 3421 at 19 10,137. 3135 at 19 11 138, 2843.atl.9 114 94. When the price is lls. multiply by 11, as taught in Multiplication, and divide the product by 20. - - Q

Case 11th–When the price is an aliquant part of a pound, , Separate the given price into such parts of a pound as may best- answer, and divide the given quantity considered as pounds, by the denominators of those parts, the sum of the quotients will be the answer.

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*8. 2s Id.being an aliquot part of £10, therefore add a cipher to the

given quantity, and divide b 12 and 8.

24, 165. 209 at 5 7 166. 234 at 5 10; 167.707 at 5 168. 51 l at 7 1 169. 237 at 7 8; 170.401 at 7 11 171. 912 at 13 5 172. 315 at 9 4 173. 444 at 9 10 174. 237 at 15 0 175. 173 at 11 9 176, 853 at 12 -7 177. 845 at 17 178, 308 at 13 l l 179. 649 at 14 3 180. 239 at 8 181. 301 at 15 4 182.679 at 16 10% 183. 166 at 10 184. 375 at 18 5; 185. 875 at 18 9 186. 897 at 19 Case 12th.-When the price is 36 s. d. - - Consider the given quantity as pounds, then multiply by the pounds of the price, and for the shillings and pence proceed as in the former case, the several quotients and first product added together, will be the answer.

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1930, 18s 1}d 843 at 3 10 9 3

- 12 0 ; at 1 13 9 - - — =+3. * , 10 0– *::: 10 * - 1, 8–4, 44 15 0 6=o, 21 l 6 1=ool 2 4 9 3= #| 10 109 1478! 19 9 2982] 2 3 - - 847 at 1 18 9 . 375 1 17 4 18 0–,”,762 6 - 16 0--or 300 = , , 31 15 3 1 4=r'rl 25 1641/ 1' 3 700l

Note.—When the price is 11 with any number of shillings and pence annexed, the multiplication by the unit may be omitted, and the given quantity added in as pounds,

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