 | Robert Simson - 1762 - 488 σελίδες
...&c, Q..ED PROP. PROP. XXXVI. THEOR. T)ARALLEI.oGRAMs upon equal bafes and between the Sobk I. ± fame parallels, are equal to one another. Let ABCD, EFGH be parallelograms upon equal bafes BC, FG, and between the fame I parallels AH, BG ; the **• parallelogram ABCD is equal to EFGH.... | |
 | 1867 - 964 σελίδες
...any point in tho straight line HK, produced both ways indefinitely. Triangles also which stand npon equal bases and between the same parallels are equal to one another. Thus, the triangles LNG, M o F, which „ ._ stand on equal bases, NG, F o, and K between the same... | |
 | Robert Simson - 1775 - 534 σελίδες
...another. LetABCD.EFGHbe » parallelograms upon e— £*• qual bafes BC, FG, and between the fame parallels AH, BG ; the parallelogram ABCD is equal to EFGH. Join BE, CH; and-r> becaufe BC is equal to-" FG, and FG to " EH, BC is equal to EH ; and they are pa- a 34- r. rallels,... | |
 | Euclid - 1781 - 552 σελίδες
...bale, &c. OED PROP. Book I. PROP. XXXVI. THEO R. LLELoGRAMR upon equal bafes.and between the £une parallels, are equal to one another. Let ABCD, EFGH be parallelograms upon e qual bafes BC, FG, and between the fame parallel* AH, BG ; theparal. lelogram ABCD is equal to tFGH.... | |
 | Alexander Ingram - 1799 - 374 σελίδες
...equal to one another. Let ABCD, EFGH be parallelogiams upoii equal bafes BC, FG, aud between the fame parallels AH, BG ; the parallelogram ABCD is equal to EFGH. Join BE, CH ; and becaufe BC is equal to FG, and FG to a EH, BC is equal to EH ; nnd they are parallels, and joined a... | |
 | Robert Simson - 1804 - 530 σελίδες
...bafe, &c. QJE. D. Book I. PROP. XXXVI. THEOR. |ARALLELooRAMS upon equal bafes and between the fame parallels, are equal to one another, Let ABCD, EFGH be parallelograms upon equal bafes BC, FG, and between the fame parallels AH, BG; the parallelogram ABCD is equal to EFGH. Join... | |
 | John Playfair, Euclid - 1804 - 468 σελίδες
...the fame bafe, &c. Q^ ED PROP. XXXVI. THEOR. PARALLELoGRAMS upon equal bafes, and between the fame parallels, are equal to one another. Let ABCD, EFGH be parallelograms upon equal bafes BC, FG, and between the fame parallels AH, BG ; the parallelogram ABCD is equal to EFGH. ^ Join... | |
 | Robert Simson - 1806 - 546 σελίδες
...ABC is'equal to the triangle DBC. Wherefore, triangles, fee, QE D, PROP. XXXVIII. THEOR. TRIANGLES upon equal bases, and between the same parallels, are equal to one another. Let the triangles ABC, DEF be upon equal bases BC, EF, and between the same parallels BF, AD : the triangle... | |
 | John Playfair - 1806 - 320 σελίδες
...Ax. ABC is equald to the triangle DBC. Wherefore, triangles, &c. QED PROP. XXXVIII. THEOR. TRIANGLES upon equal bases, and between the same parallels, are equal to one another. Let the triangles ABC, DEF be upon equal bases BC, EF, and between the same parallels BF, AD ; the triangle... | |
 | Robert Gibson - 1806 - 486 σελίδες
...ABCD being a parallelogram, AB will be=CD and AD = BC, THEOREM XIII, All parallelograms on the same or equal bases and between the same parallels, are equal to one ' another, that is, if BD^GH, and the lines BH and AF parallel, then the parallel0gram ABDC ^BDFE=EFHG. .fig.... | |
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Parallelograms upon equal bases, and between the same parallels, are equal to one another. 
