 | Adrien Marie Legendre - 1819 - 574 σελίδες
...a given point to the same straight line, which is impossible (54). -. ' THEOREM. Fig;. 50. 102. In the same circle, or in equal circles, equal arcs are subtended by equal c/wrds, and conversely, equal chords subtend equal arcs. Demonstration. The radius AC (Jig. 50) being... | |
 | Adrien Marie Legendre, John Farrar - 1825 - 280 σελίδες
...lines drawn from a given point to the same straight line, which is impossible (54). THEOREM. 7 102. In the same circle, or in equal circles, equal arcs are...chords, and conversely, equal chords subtend equal arcs. Fig. 50. Demonstration. The radius AC (fig. 50) being equal to the radius £0, and the arc AMD equal... | |
 | Adrien Marie Legendre - 1825 - 570 σελίδες
...lines drawn from a given point to the same straight line. which is impossible (54). THEOREM. 102. In the same circle, or in equal circles, equal arcs are...chords, and conversely, equal chords subtend equal arcs. Fig. so. Demonstration. The radius AC (fig. 50) being equal to the radius EO, and the arc AMD equal... | |
 | Adrien Marie Legendre, John Farrar - 1825 - 294 σελίδες
...lines drawn from a given point to the same straight lin which is impossible (54). THEOREM. 102. In the same circle, or in equal circles, equal arcs are...chords, and conversely, equal chords subtend equal arcs. .Fig. 50. Demonstration. The radius AC (Jig. 50) being equal to the radius £0, and the arc AMD equal... | |
 | James Hayward - 1829 - 218 σελίδες
...equal angks at the centre are measured by equal arcs ; and equal arcs subtend equal angles. (2). In the same circle, or in equal circles, equal arcs are subtended by equal chords ; and when, in the same circle, the chord. are equal, the arcs are equal. As the triangle would not be changed... | |
 | Pierce Morton - 1830 - 584 σελίδες
...another. And, in like manner, the converse. Therefore, &c. Cor. 1. (Eue. iii. 28 and 29.) In the same or in equal circles, equal arcs are subtended by equal chords ; and conversely (11. Cor.). Cor. 2. By a similar demonstration it may be shown that in the same or in equal circles,... | |
 | 1835 - 684 σελίδες
...another. And, in like manner, the converse. Therefore, &c. Cor. 1. (Eue. iii. 28 and 29.) In the same or in equal circles, equal arcs are subtended by equal chords ; and conversely (11. Cor.). Cor. 2. By a similar demonstration it may be shown that in the same or in equal circles,... | |
 | Adrien Marie Legendre - 1836 - 394 σελίδες
...drawn from the same point to the same straight line, which is impossible (Book I. Prop. XV. Cor. 2.). PROPOSITION IV. THEOREM. In the same circle, or in...and, conversely, equal chords subtend equal arcs. Kate. When reference is made from one proposition to another, in th« ! Book, the number of the proposition... | |
 | Adrien Marie Legendre - 1837 - 376 σελίδες
...same straight line, winch is impossible (Book I. Prop. XV. C«r. 2.). PROPOSITION IV. THEOREM. In ihe same circle, or in equal circles, equal arcs are subtended...; and, conversely, equal chords subtend equal arcs Note. When reference is made from one proposition to another, in th» Mine Book, the number of the... | |
 | Benjamin Peirce - 1837 - 216 σελίδες
...obtuse angle ; for it has for its measure the half of an arc greater than a semicircumference. 111. Theorem. In the same circle, or in equal circles, equal arcs are subtended by equal chords. Demonstration. Let the arc AB (fig. 52) be equal to ihe arc BC. ' Join AC; and, in the triangle ABC,... | |
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THEOREM. In the same circle, or in equal circles, equal arcs are subtended by equal chords ; and, conversely, equal chords subtend equal arcs. 
