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2. Name the prime numbers from 1 to 53. prime numbers from 53 to 101.

Name the

3. Write the numbers from 1 to 100, and cut out all the composite numbers, leaving the primes.

4. What is the second power of 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20?

5. What is the 3d power of each of the above? The 4th power? The 5th power? The 6th power?

PRINCIPLES.

1. Every composite number is equal to the product of its factors.

2. A factor of a number is a factor of any number of times that number.

108. To form composite numbers out of any factors. 1. Form a composite number out of 4, 9, and 5. SOLUTION.-A composite number formed out of the factors, 4, 9, and 5, is equal to their product, which is

180.

WRITTEN EXERCISES.

Form composite numbers out

OPERATION.

4x9x5=180

2. Of 5, 6, 7, and 8.

3. Of two 2's, 3, and 7.

4. Of three 3's, four 2's, and two 5's.
5. Find a number consisting of four 5's.
6. Find the fifth power of 3, of 4, of 7.

Ans. 243;

Ans. 1680.

Ans. 84.

Ans. 10800.
Ans. 625

1024; 16807.

7. Form a composite number out of the first four prime numbers after unity.

Ans. 210.

8. Form a composite number out of all the prime numbers between 11 and 29. Ans. 96577. 9. Form all the composite numbers you can out of 2, 3, Ans. 6; 10; 14; 15; 21; etc.

5, and 7.

10. Form all the composite numbers you can out of 2, 3, 5, 7, and 11. Ans. 6; 10; 14; 22; 15; 21; etc. 11. Find a composite number consisting of three factors, the first being 2, the second being twice as great, and the third three times as great.

Ans 48.

DIVISIBILITY OF COMPOSITE NUMBERS.

109. Composite Numbers can be divided by the factors which produce them.

110. The Factors of many composite numbers may be seen by inspection from the following principles:

PRINCIPLES.

1. A number is divisible by 2 when the right hand term is zero or an even digit.

For, the number is evidently an even number, and all even numbers are divisible by 2.

2. A number is divisible by 3 when the sum of the digits is divisible by 3.

This may be shown by trying several numbers, and, seeing that it is true with these, we infer that it is true with all. A rigid demonstration is too difficult for this place.

3. A number is divisible by 4 when the two right hand terms are ciphers, or when the number they express is divisible by 4.

If the two right hand terms are ciphers, the number equals a number of hundreds, and since 100 is divisible by 4, any number of hundreds is divisible by 4.

If the number expressed by the two right hand digits is divisible by 4, the number will consist of a number of hundreds plus the number expressed by the two right hand digits (thus 1232=1200+32); and since both of these are divisible by 4, their sum, which is the number itself, is divisible by 4.

4. A number is divisible by 5 when its right hand term is 0 or 5.

When the unit figure is 0, the last partial dividend must be 0, 10, 20, 30, or 40, each of which is divisible by 5. When the unit figure is 5, the last partial dividend must be 15, 25, 35, or 45, each of which is divisible by 5. Therefore, etc.

5. A number is divisible by 6 when it is even, and the sum of the digits is divisible by 3.

Since the number is even it is divisible by 2, and since the sum of the digits is divisible by 3 the number is divisible by 3, and since it contains both 2 and 3, it will contain their product, 3×2, or 6.

6 A number is divisible by 8 when the three right hand terms are ciphers, or when the number expressed by them is divisible by 8.

If the three right hand terms are ciphers, the number equals a number of thousands, and since 1000 is divisible by 8, any number of thousands is divisible by 8.

If the number expressed by the three right hand digits is divisible by 8, the entire number will consist of a number of thousands plus the num ber expressed by the three right hand digits (thus 17368-17000+368) and since both of these parts are divisible by 8, their sum, which is the number itself, is divisible by 8.

7. A number is divisible by 9 when the sum of the digits is divisible by 9.

This may be shown by trying several numbers, and, seeing that it is true with these, we can infer that it is true with all. It may also be rigidly demonstrated.

8. A number is divisible by 10 when the unit figure is 0. For, such a number equals a number of tens, and any number of tens is divisible by 10, hence the number is divisible by 10.

NOTE.-1. A number is divisible by 7 when the sum of the odd numerical periods, minus the sum of the even numerical periods, is divisible by 7.

2. A number is divisible by 11 when the difference between the sums of the digits in the odd places and in the even places is divisible by 11, or when this difference is 0.

3 These two principles are rather curious than useful. For their demonstration see Higher Arithmetic.

INTRODUCTION TO FACTORING.

MENTAL EXERCISES.

1. Name the prime numbers from 1 to 50.

2. Name the composite numbers from 0 to 50.

3. Name some of the factors or makers of 12, 15, 21, 28, 36, 54, 72. 4. Name the prime numbers which are factors of 12, 18, 20, 24, 36, 54, and 72.

5. What shall we call the factors of numbers when they are prime numbers? Ans. The Prime Factors.

6. Name the prime factors of 12, 16, 18, 20, 24, 30, 32, 36, 40, 45, 50, 60, and 80.

7. Illustrate the principle that the factors of a number are divisors of the number.

8. How then can we find the factors of a number? Ans. By find ing the divisors of a number.

9. How can we find the divisors of a number? Ans. By trial, aided by the principles of Art. 110.

10. What do we call that subject of arithmetic which treats of find. ing the factors of numpers? Ans. Factoring.

11. How then may we define the subject of Factoring?

FACTORING.

111. Factoring is the process of finding the factors of composite numbers. Unity and the number itself are not regarded as factors.

112. The Factors of a composite number are the numbers which multiplied together will produce it; thus, 3 and 4 are factors of 12.

113. The Prime Factors of a composite number are the prime numbers which multiplied together will produce it; thus, 2, 2, and 3 are the prime factors of 12.

114. One of the two equal factors of a number is called its 2d, or square root; one of the 3 equal factors, its 3d, or cube root, etc.; thus, 3 is the 2d root of 9, 2 the 3d root of 8.

PRINCIPLES.

1. A divisor of a number, excepting unity and itself, is a factor of that number.

2. A divisor of a factor of a number, excepting unity, is a factor of the number.

3. A number is divisible by its prime factors or by any product of them.

4. A number is divisible only by its prime factors or by some product of them, or by unity.

CASE 1.

115. To resolve a number into its prime factors. 1. Find the prime factors of 105.

SOLUTION.-Dividing by 3, we find that 3 is a factor of 105 (Prin. 1). Dividing the quotient by 5, we find that 5 and 7 are factors of 35 (Prin. 2), and since these numbers 3, 5, and 7, are prime numbers, they are be prime factors of 105.

OPERATION.

3)105

5)35
7

Rule.-I. Divide the given number by any prime number greater than 1, that will exactly divide it.

II. Divide the quotient, if composite, in the same manner, und thus continue until the quotient is prime.

III. The divisors and last quotient will be the prime fac tors required.

[blocks in formation]

116. To resolve a number into equal factors. 1. Find the two equal factors of 1225.

SOLUTION. We first resolve the number into its prime factors. Now since there are two 5's, we take one 5 for each factor; and since there are two 7's, we take one 7 for each factor; hence each of the two equal factors is 5x7, or 35. Therefore 35 is one of the two equal factors of 1225.

OPERATION.

5)1225

5)245

7)49

7

5x7=35

Rule.-I. Resolve the number into its prime factors.

II. Take the continued product, of one of each of the two equal factors, when we wish the two equal factors, one of each of the three, for the three equal factors, etc.

2. Find the two equal factors of 16, 36, 100, 196, 256, 324, 900, 1296, 2025. Ans. 4, 4; 6, 6; 10, 10; 14, 14, etc. 3. Find the square root of 225, 576, 1764, 3136, 3969, 5184 Ans. 15; 24; 42; 56; 63; 72.

4. Find the cube root of 27, 64, 125, 216, 512, 1000.

Ans. 3; 4; 5; 6; 8; 10.

5. Find the fourth root of 16, 81, 256, 1296, 4096, 20736

Ans. 2; 3; 4; 6; 8; 12.

6. Find the fifth root of 32; 243; 1024; 3125.

Ans. 2; 3; 4; 5.

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