Find a common measure, by dividing the greater term by the less, and this divisor by the remainder, and so on, always dividing the last divisor' by the last remainder, till nothing remains, the last divisor is the common measure.* 2. Divide both of the... Daboll's Schoolmaster's Assistant - Σελίδα 156των Nathan Daboll - 1828 - 247 σελίδεςΠλήρης προβολή - Σχετικά με αυτό το βιβλίο
| Daniel Adams - 1810 - 190 σελίδες
...divisor of two numbers : Divide the greater number by the less, and that divisor by the remainder, and so on, always dividing the last divisor by the last remainder, till nothing remain. The last divisor will be the greatest common divisor required. Note. It is evident, that, when... | |
| Nathan Daboll - 1818 - 246 σελίδες
...a common measure, by dividing the greater term by the less, and this divisor by the remainder, and so on, always dividing the last divisor' by the last...2. Divide both of the terms of the fraction by the common measure, and the quotients will make the fraction required. • *Tofmd the greatest common measure... | |
| George G. Carey - 1818 - 602 σελίδες
...RULE. Divide the greater number by the less, and this divisor by the remainder. Proceed in this manner, always dividing the last divisor by the last remainder, till nothing remains; the last divisor is the greatest common measure. EXAMPLE. Required the greatest common measure of 84 and 144. 84)144(1 84 60)84(1... | |
| Bewick Bridge - 1818 - 254 σελίδες
...the greatest common measure of two numbers. "• Divide the greater by the lesser, and the preceding divisor by " the last remainder, till nothing remains ; the last divisor is " the, greatest common measure." To find the greatest common measure of three. numbers, a, l, с ; let d be... | |
| John Mason Good - 1819 - 694 σελίδες
...term by the less ; then divide the divisor by the remainder, if there be any, and so on continually, always dividing the last divisor by the last remainder, till nothing remains; and then is the last divisor the greatest common measure sought. For a demonstration, see Manning's... | |
| Daniel Adams - 1820 - 242 σελίδες
...continuing so to do till nothing remains ; the last divisor is the common measure ; then divide both terms of the fraction by the com* mon measure, * and the quotients will express the fraction required. 1. Reduce }$ff to its lowest terms. 1080)1224(1 1080 144)1080(7 1008... | |
| Bewick Bridge - 1821 - 284 σελίδες
...finding the greatest common measure of two numbers; " Divide the greater by the lesser, and the preceding divisor by " the last remainder, till nothing remains ; the last divisor is " the greatest common measure." To find the greatest common measure of three numbers, a, b, с ; let d be... | |
| Nathan Daboll - 1823 - 262 σελίδες
...a common measure, by dividing the greater term by the less, and this divisor by the remainder, and so on, always dividing the last divisor; by the last...remains, the last divisor is the common measure.* •i 2. Divide both of the terms of the fraction by the common measure, and the quotients will make... | |
| Nathan Daboll - 1825 - 248 σελίδες
...temí by the less, and this divisor by the remainder, and so on, always dividing the last divisorjby the last remainder, till nothing remains, the last...2. Divide both of the terms of the fraction by the common measure, and the quotients will make the fraction required. 'Jlojind the greatest common measure... | |
| Nicolas Pike, Dudley Leavitt - 1826 - 214 σελίδες
...If there be two pumbers only, divide the greater by the less, and this divisor by the remainder, and so on, always dividing the last divisor by the last remainder, till nothing remain ; then will the last divisor be the greatest common measure required. 2. When there are more... | |
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