The Synoptical Euclid; Being the First Four Books of Euclid's Elements of Geometry from the Edition of Dr. Robert Simson ... With Exercises. By S. A. Good ... Second Edition |
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Αποτελέσματα 1 - 5 από τα 17.
Σελίδα 9
... be equal to the base EF ; and the triangle ÅBC to the triangle DEF ; and the other angles , to which the equal sides are opposite , shall be equal , each to each , viz . the angle ABC to the angle DEF , and the angle ACB to DFE .
... be equal to the base EF ; and the triangle ÅBC to the triangle DEF ; and the other angles , to which the equal sides are opposite , shall be equal , each to each , viz . the angle ABC to the angle DEF , and the angle ACB to DFE .
Σελίδα 10
The angles at the base of an isosceles triangle are equal to one another ; and if the equal sides be produced ... AC , be produced to D and E , the angle ABC shall be equal to the angle ACB , and the apgle CBD to the angle BCE .
The angles at the base of an isosceles triangle are equal to one another ; and if the equal sides be produced ... AC , be produced to D and E , the angle ABC shall be equal to the angle ACB , and the apgle CBD to the angle BCE .
Σελίδα 11
And it has also been proved that the angle FBC is equal to the angle GCB , which are the angles upon the other side of ... Let ABC be a triangle having the angle ABC equal to the angle ACB ; the side AB is also equal to the side AČ .
And it has also been proved that the angle FBC is equal to the angle GCB , which are the angles upon the other side of ... Let ABC be a triangle having the angle ABC equal to the angle ACB ; the side AB is also equal to the side AČ .
Σελίδα 12
The angle BDC is equal to the angle BCD ; but it has been demonstrated to be greater than it , which is impossible . But if one of the vertices , as D , be within the other triangle ACB ; produce AC , AD to E , F ; therefore because 4C ...
The angle BDC is equal to the angle BCD ; but it has been demonstrated to be greater than it , which is impossible . But if one of the vertices , as D , be within the other triangle ACB ; produce AC , AD to E , F ; therefore because 4C ...
Σελίδα 14
the angle ACB by the straight line CD . AB is cut into two equal parts in the point D. ) C A. B Because AC is equal to CB , and CD common to the two triangles ACD , BCD ; 1 . The two sides AC , CD are equal to BC , CD , each to each ...
the angle ACB by the straight line CD . AB is cut into two equal parts in the point D. ) C A. B Because AC is equal to CB , and CD common to the two triangles ACD , BCD ; 1 . The two sides AC , CD are equal to BC , CD , each to each ...
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AB is equal ABC is equal ABCD angle ABC angle ACB angle AGH angle BAC angle BCD angle equal base BC bisected centre circle ABC circumference coincide common demonstrated describe diameter distance divided double draw equal angles exterior angle extremity fall figure four given circle given point given straight line gnomon greater impossible inscribed join less Let ABC Let the straight likewise manner meet opposite angles parallel parallelogram pass pentagon perpendicular point F PROBLEM produced Q.E.D. PROP reason rectangle contained rectilineal figure remaining angle right angles segment semicircle shown side BC sides square of AC straight line AC Take touches the circle triangle ABC twice the rectangle wherefore whole
Πληροφορίες βιβλιογραφίας
| Τίτλος | The Synoptical Euclid; Being the First Four Books of Euclid's Elements of Geometry from the Edition of Dr. Robert Simson ... With Exercises. By S. A. Good ... Second Edition |
| Συγγραφείς | EUCLID., Samuel A. GOOD |
| Έκδοση | 2 |
| Εκδότης | Charles Henry Law, 1854 |
| Πρωτότυπο από | Η Βρετανική βιβλιοθήκη |
| Ψηφιοποιήθηκε στις | 10 Δεκ. 2013 |
| Μέγεθος | 120 σελίδες |
| Εξαγωγή αναφοράς | BiBTeX EndNote RefMan |