The Synoptical Euclid; Being the First Four Books of Euclid's Elements of Geometry from the Edition of Dr. Robert Simson ... With Exercises. By S. A. Good ... Second Edition |
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Σελίδα 9
AB to DE , and AC to DF ; and the angle BAC equal to the angle EDF : the base BC shall be equal to the base EF ; and the triangle ÅBC to the triangle DEF ; and the other angles , to which the equal sides are opposite , shall be equal ...
AB to DE , and AC to DF ; and the angle BAC equal to the angle EDF : the base BC shall be equal to the base EF ; and the triangle ÅBC to the triangle DEF ; and the other angles , to which the equal sides are opposite , shall be equal ...
Σελίδα 10
The angles at the base of an isosceles triangle are equal to one another ; and if the equal sides be produced ... and the angle BFC is equal to the angle CGB , and the base BC is common to the two triangles BFC , CGB ; wherefore ( I. 4. ) ...
The angles at the base of an isosceles triangle are equal to one another ; and if the equal sides be produced ... and the angle BFC is equal to the angle CGB , and the base BC is common to the two triangles BFC , CGB ; wherefore ( I. 4. ) ...
Σελίδα 11
which are the angles at the base of the triangle ABC . And it has also been proved that the angle FBC is equal to the angle GCB , which ... Therefore because in the triangles DBC , ACB , DB is equal to AC , and BC common to both , 1 .
which are the angles at the base of the triangle ABC . And it has also been proved that the angle FBC is equal to the angle GCB , which ... Therefore because in the triangles DBC , ACB , DB is equal to AC , and BC common to both , 1 .
Σελίδα 13
AB to DE , and AC to DF ; and also the base BC equal to the base EF . The angle BAC is equal to the angle EDF . D G А F B For if the triangle ABC be applied to DEF , so that the point B be on E , and the straight line BC upon EF ; 1 .
AB to DE , and AC to DF ; and also the base BC equal to the base EF . The angle BAC is equal to the angle EDF . D G А F B For if the triangle ABC be applied to DEF , so that the point B be on E , and the straight line BC upon EF ; 1 .
Σελίδα 14
The base DF is equal to the base EF ; therefore ( I. 8. ) 3 . The angle DAF is equal to the angle EAF ... The two sides AC , CD are equal to BC , CD , each to each ; and ( Constr . ) 2 . The angle ACD is equal to the angle BCD ...
The base DF is equal to the base EF ; therefore ( I. 8. ) 3 . The angle DAF is equal to the angle EAF ... The two sides AC , CD are equal to BC , CD , each to each ; and ( Constr . ) 2 . The angle ACD is equal to the angle BCD ...
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AB is equal ABC is equal ABCD angle ABC angle ACB angle AGH angle BAC angle BCD angle equal base BC bisected centre circle ABC circumference coincide common demonstrated describe diameter distance divided double draw equal angles exterior angle extremity fall figure four given circle given point given straight line gnomon greater impossible inscribed join less Let ABC Let the straight likewise manner meet opposite angles parallel parallelogram pass pentagon perpendicular point F PROBLEM produced Q.E.D. PROP reason rectangle contained rectilineal figure remaining angle right angles segment semicircle shown side BC sides square of AC straight line AC Take touches the circle triangle ABC twice the rectangle wherefore whole