The Synoptical Euclid; Being the First Four Books of Euclid's Elements of Geometry, from the Edition of Dr. Robert Simson ... With ExercisesCharles Henry Law, 1854 - 120 σελίδες |
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Αποτελέσματα 1 - 5 από τα 31.
Σελίδα 13
... bisect a given rectilineal angle , that is , to divide it into two equal angles . Let BAC be the given rectilineal angle , it is required to bisect it . Take any point Din AB , and from AC cut ( I. 3. ) off AE equal to AD ; join DE ...
... bisect a given rectilineal angle , that is , to divide it into two equal angles . Let BAC be the given rectilineal angle , it is required to bisect it . Take any point Din AB , and from AC cut ( I. 3. ) off AE equal to AD ; join DE ...
Σελίδα 14
... bisected by the straight line AF . Which was to be done . PROP . X. - PROBLEM . To bisect a given finite straight line , that is , to divide it into two equal parts . Let AB be the given straight line ; it is required to divide it into ...
... bisected by the straight line AF . Which was to be done . PROP . X. - PROBLEM . To bisect a given finite straight line , that is , to divide it into two equal parts . Let AB be the given straight line ; it is required to divide it into ...
Σελίδα 16
... bisect ( I. 10. ) FG in H , and join CH ; the straight line CH , drawn from the given point C , is perpendicular to the given straight line AB . C E II G B D Join CF , CG ; and because FH is equal to HG , and HC common to the two ...
... bisect ( I. 10. ) FG in H , and join CH ; the straight line CH , drawn from the given point C , is perpendicular to the given straight line AB . C E II G B D Join CF , CG ; and because FH is equal to HG , and HC common to the two ...
Σελίδα 19
... Bisect ( I. 10. ) AC in E , join BE and produce it to F , and make EF equal to BE ; join also FC , and produce AC to G ... bisected , it may be demonstrated that the angle BCG that is ( I. 15. ) 6. The angle ACD is greater than the angle ...
... Bisect ( I. 10. ) AC in E , join BE and produce it to F , and make EF equal to BE ; join also FC , and produce AC to G ... bisected , it may be demonstrated that the angle BCG that is ( I. 15. ) 6. The angle ACD is greater than the angle ...
Σελίδα 39
... Bisect ( I. 10. ) BC in E , join AE , and at the point E in the straight line EC make ( I. 23. ) the angle CEF equal to D ; and through A draw ( I 31. ) AFG parallel to EC , and through C draw CG parallel to EF . Therefore ( I. 34. Def ...
... Bisect ( I. 10. ) BC in E , join AE , and at the point E in the straight line EC make ( I. 23. ) the angle CEF equal to D ; and through A draw ( I 31. ) AFG parallel to EC , and through C draw CG parallel to EF . Therefore ( I. 34. Def ...
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AB is equal AC is equal adjacent angles angle ABC angle ACB angle AGH angle BAC angle BCD angle EDF angle equal base BC bisected circle ABC circumference diameter double draw equal angles equal Constr equal Hyp equal straight lines equal to BC equilateral and equiangular EUCLID'S ELEMENTS exterior angle given circle given point given rectilineal angle given straight line given triangle gnomon greater inscribed interior and opposite less Let ABC Let the straight likewise opposite angles parallel to CD parallelogram pentagon perpendicular point F produced Q.E.D. PROP rectangle AE rectangle contained remaining angle required to describe right angles semicircle side BC square of AC straight line AB straight line AC straight line drawn touches the circle triangle ABC twice the rectangle