The Synoptical Euclid; Being the First Four Books of Euclid's Elements of Geometry from the Edition of Dr. Robert Simson ... With Exercises. By S. A. Good ... Second Edition |
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Σελίδα 3
And this point is called the centre of the circle . XVII . A diameter of a circle is a straight line drawn through the centre , and terminated both ways by the circumference . XVIII . A semicircle is the figure contained by a diameter ...
And this point is called the centre of the circle . XVII . A diameter of a circle is a straight line drawn through the centre , and terminated both ways by the circumference . XVIII . A semicircle is the figure contained by a diameter ...
Σελίδα 5
That a terminated straight line may be produced to any length in a straight line . III . And that a circle may be described from any centre , at any distance from AXIOMS . I. Things which are equal to the same. that centre . POSTULATES.
That a terminated straight line may be produced to any length in a straight line . III . And that a circle may be described from any centre , at any distance from AXIOMS . I. Things which are equal to the same. that centre . POSTULATES.
Σελίδα 7
From the centre A , at the distance AB , describe ( Postulate 3. ) the circle BCD ; and from the centre B , at the distance B4 , describe the circle ACE ; and from the point C , in which the circles cut one another , draw ( Post . 1. ) ...
From the centre A , at the distance AB , describe ( Postulate 3. ) the circle BCD ; and from the centre B , at the distance B4 , describe the circle ACE ; and from the point C , in which the circles cut one another , draw ( Post . 1. ) ...
Σελίδα 8
Because the point B is the centre of the circle CGH , ( Def . 15. ) 1 . BC is equal to BG ; and because D is the centre of the circle GLK , 2 . DL is equal to DG ; and DA , DB , parts of them are equal ( Construction ) ; therefore ...
Because the point B is the centre of the circle CGH , ( Def . 15. ) 1 . BC is equal to BG ; and because D is the centre of the circle GLK , 2 . DL is equal to DG ; and DA , DB , parts of them are equal ( Construction ) ; therefore ...
Σελίδα 16
It is required to draw a straight line perpendicular to AB from the point C. Take any point D upon the other side of AB , and from the centre C , at the distance CD , describe ( Post . 3. ) the circle EGF meeting , AB in F , G ; and ...
It is required to draw a straight line perpendicular to AB from the point C. Take any point D upon the other side of AB , and from the centre C , at the distance CD , describe ( Post . 3. ) the circle EGF meeting , AB in F , G ; and ...
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AB is equal ABC is equal ABCD angle ABC angle ACB angle AGH angle BAC angle BCD angle equal base BC bisected centre circle ABC circumference coincide common demonstrated describe diameter distance divided double draw equal angles exterior angle extremity fall figure four given circle given point given straight line gnomon greater impossible inscribed join less Let ABC Let the straight likewise manner meet opposite angles parallel parallelogram pass pentagon perpendicular point F PROBLEM produced Q.E.D. PROP reason rectangle contained rectilineal figure remaining angle right angles segment semicircle shown side BC sides square of AC straight line AC Take touches the circle triangle ABC twice the rectangle wherefore whole