The Synoptical Euclid; Being the First Four Books of Euclid's Elements of Geometry from the Edition of Dr. Robert Simson ... With Exercises. By S. A. Good ... Second Edition |
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Σελίδα 7
the circle BCD ; and from the centre B , at the distance B4 , describe the circle ACE ; and from the point C , in which the circles cut one another , draw ( Post . 1. ) the straight lines CA , CB , to the points 4 , B ; ABC shall be an ...
the circle BCD ; and from the centre B , at the distance B4 , describe the circle ACE ; and from the point C , in which the circles cut one another , draw ( Post . 1. ) the straight lines CA , CB , to the points 4 , B ; ABC shall be an ...
Σελίδα 24
Again , because G is the centre of the circle LKH , 3 . GH is equal to GK ; but GH is equal to C ; therefore also 4 ... Let ABC , DEF , be two triangles which have the two sides AB , AC , equal to the two DE , DF , each to each , viz .
Again , because G is the centre of the circle LKH , 3 . GH is equal to GK ; but GH is equal to C ; therefore also 4 ... Let ABC , DEF , be two triangles which have the two sides AB , AC , equal to the two DE , DF , each to each , viz .
Σελίδα 66
I. PROBLEM , To find the centre of a given circle . Let ABC be the given circle ; it is required to find its centre . Draw within it any straight line AB , and bisect ( I. 10. ) AB in D ; from the point D draw ( I. 11. ) ...
I. PROBLEM , To find the centre of a given circle . Let ABC be the given circle ; it is required to find its centre . Draw within it any straight line AB , and bisect ( I. 10. ) AB in D ; from the point D draw ( I. 11. ) ...
Σελίδα 67
Let ABC be a circle , and 4 , B , any two points in the circumference ; the straight line drawn from A to B shall fall within the circle . C А E B For if AB do not fall within the circle , let it fall , if possible , without , as AEB ...
Let ABC be a circle , and 4 , B , any two points in the circumference ; the straight line drawn from A to B shall fall within the circle . C А E B For if AB do not fall within the circle , let it fall , if possible , without , as AEB ...
Σελίδα 69
Let the two circles ABC , CDG , cut one another in the points B , C ; they have not the same centre G E B For , if it be possible , let E be their centre : join ... in F and G. And because E is the centre of the circle ABC , ( I. Def .
Let the two circles ABC , CDG , cut one another in the points B , C ; they have not the same centre G E B For , if it be possible , let E be their centre : join ... in F and G. And because E is the centre of the circle ABC , ( I. Def .
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AB is equal ABC is equal ABCD angle ABC angle ACB angle AGH angle BAC angle BCD angle equal base BC bisected centre circle ABC circumference coincide common demonstrated describe diameter distance divided double draw equal angles exterior angle extremity fall figure four given circle given point given straight line gnomon greater impossible inscribed join less Let ABC Let the straight likewise manner meet opposite angles parallel parallelogram pass pentagon perpendicular point F PROBLEM produced Q.E.D. PROP reason rectangle contained rectilineal figure remaining angle right angles segment semicircle shown side BC sides square of AC straight line AC Take touches the circle triangle ABC twice the rectangle wherefore whole