The Synoptical Euclid; Being the First Four Books of Euclid's Elements of Geometry from the Edition of Dr. Robert Simson ... With Exercises. By S. A. Good ... Second Edition |
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Αποτελέσματα 1 - 5 από τα 34.
Σελίδα 9
... was to be demonstrated . PROP . V. - THEOREM . The angles at the iş BOOK I .-- PROP . IV . 9 shall be equal, each to each, viz. ...
... was to be demonstrated . PROP . V. - THEOREM . The angles at the iş BOOK I .-- PROP . IV . 9 shall be equal, each to each, viz. ...
Σελίδα 10
... and their remaining angles are equal , each to each , to which the equal sides are opposite ; therefore 5 . The angle FBC is equal to the angle GCB , and the angle BCF to the angle CBG . And since it has been demonstrated , that the ...
... and their remaining angles are equal , each to each , to which the equal sides are opposite ; therefore 5 . The angle FBC is equal to the angle GCB , and the angle BCF to the angle CBG . And since it has been demonstrated , that the ...
Σελίδα 12
The angle BDC is equal to the angle BCD ; but it has been demonstrated to be greater than it , which is impossible . But if one of the vertices , as D , be within the other triangle ACB ; produce AC , AD to E , F ; therefore because 4C ...
The angle BDC is equal to the angle BCD ; but it has been demonstrated to be greater than it , which is impossible . But if one of the vertices , as D , be within the other triangle ACB ; produce AC , AD to E , F ; therefore because 4C ...
Σελίδα 15
... ECF , is a right angle . Wherefore , from the given point C , in the given straight line AB , 5 . FC has been drawn at right angles to AB . Which was to be done . COR . - By help of this problem , it may be demonstrated that two ...
... ECF , is a right angle . Wherefore , from the given point C , in the given straight line AB , 5 . FC has been drawn at right angles to AB . Which was to be done . COR . - By help of this problem , it may be demonstrated that two ...
Σελίδα 17
... EBD , have been demonstrated to be equal to the same three angles ; and things that are equal to the same are equal ( Ax . 1. ) to one another ; therefore 4 . The angles CBE , EBD , are equal to the angles DB4 , ABC ; but CBE ...
... EBD , have been demonstrated to be equal to the same three angles ; and things that are equal to the same are equal ( Ax . 1. ) to one another ; therefore 4 . The angles CBE , EBD , are equal to the angles DB4 , ABC ; but CBE ...
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AB is equal ABC is equal ABCD angle ABC angle ACB angle AGH angle BAC angle BCD angle equal base BC bisected centre circle ABC circumference coincide common demonstrated describe diameter distance divided double draw equal angles exterior angle extremity fall figure four given circle given point given straight line gnomon greater impossible inscribed join less Let ABC Let the straight likewise manner meet opposite angles parallel parallelogram pass pentagon perpendicular point F PROBLEM produced Q.E.D. PROP reason rectangle contained rectilineal figure remaining angle right angles segment semicircle shown side BC sides square of AC straight line AC Take touches the circle triangle ABC twice the rectangle wherefore whole