The Synoptical Euclid; Being the First Four Books of Euclid's Elements of Geometry from the Edition of Dr. Robert Simson ... With Exercises. By S. A. Good ... Second Edition |
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Αποτελέσματα 1 - 5 από τα 28.
Σελίδα 7
Let AB be the given straight line ; it is required to describe an equilateral triangle upon it . ... the circle BCD ; and from the centre B , at the distance B4 , describe the circle ACE ; and from the point C , in which the circles cut ...
Let AB be the given straight line ; it is required to describe an equilateral triangle upon it . ... the circle BCD ; and from the centre B , at the distance B4 , describe the circle ACE ; and from the point C , in which the circles cut ...
Σελίδα 8
BC is equal to BG ; and because D is the centre of the circle GLK , 2 . ... Wherefore from the given point A a straight line AL has been drawn equal to the given straight line BC . Which was to be done . PROP . III .
BC is equal to BG ; and because D is the centre of the circle GLK , 2 . ... Wherefore from the given point A a straight line AL has been drawn equal to the given straight line BC . Which was to be done . PROP . III .
Σελίδα 16
the circle EGF meeting , AB in F , G ; and bisect ( I. 10. ) FG in H , and join CH ; the straight line CH , drawn from the given point C , is perpendicular to the given straight line AB . E HI A F G B Join CF , CG ; and because FH is ...
the circle EGF meeting , AB in F , G ; and bisect ( I. 10. ) FG in H , and join CH ; the straight line CH , drawn from the given point C , is perpendicular to the given straight line AB . E HI A F G B Join CF , CG ; and because FH is ...
Σελίδα 23
To make a triangle of which the sides shall be equal to three given straight lines , but any two whatever of these must be ... the circle DKL ; and from the centre G , at the distance GH , describe another circle HLK ; and join KF ...
To make a triangle of which the sides shall be equal to three given straight lines , but any two whatever of these must be ... the circle DKL ; and from the centre G , at the distance GH , describe another circle HLK ; and join KF ...
Σελίδα 24
Again , because G is the centre of the circle LKH , 3 . GH is equal to GK ; but GH is equal ... The triangle KFG has its three sides KF , FG , GK , equal to the three given straight lines A , B , C. Which was to be done . PROP . XXIII .
Again , because G is the centre of the circle LKH , 3 . GH is equal to GK ; but GH is equal ... The triangle KFG has its three sides KF , FG , GK , equal to the three given straight lines A , B , C. Which was to be done . PROP . XXIII .
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AB is equal ABC is equal ABCD angle ABC angle ACB angle AGH angle BAC angle BCD angle equal base BC bisected centre circle ABC circumference coincide common demonstrated describe diameter distance divided double draw equal angles exterior angle extremity fall figure four given circle given point given straight line gnomon greater impossible inscribed join less Let ABC Let the straight likewise manner meet opposite angles parallel parallelogram pass pentagon perpendicular point F PROBLEM produced Q.E.D. PROP reason rectangle contained rectilineal figure remaining angle right angles segment semicircle shown side BC sides square of AC straight line AC Take touches the circle triangle ABC twice the rectangle wherefore whole