The Synoptical Euclid; Being the First Four Books of Euclid's Elements of Geometry from the Edition of Dr. Robert Simson ... With Exercises. By S. A. Good ... Second Edition |
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Αποτελέσματα 1 - 5 από τα 27.
Σελίδα 8
But it has been shown that BC is equal to BG ; wherefore AL and BC are each of them equal to BG ; and things that are equal to the same are equal to one another ; therefore 4 . The straight line AL is equal to BC .
But it has been shown that BC is equal to BG ; wherefore AL and BC are each of them equal to BG ; and things that are equal to the same are equal to one another ; therefore 4 . The straight line AL is equal to BC .
Σελίδα 21
The side AC is not less than AB ; and it has been shown that it is not equal to AB ; therefore 3 . AC is greater than AB . Wherefore the greater angle , & c . Q.E.D. PROP . XX . -THEOREM . Any two sides of a triangle are together ...
The side AC is not less than AB ; and it has been shown that it is not equal to AB ; therefore 3 . AC is greater than AB . Wherefore the greater angle , & c . Q.E.D. PROP . XX . -THEOREM . Any two sides of a triangle are together ...
Σελίδα 23
The sides CE , EB , are greater than CD , DB ; but it has been shown that BA , AC , are greater than BE , EC ; much more then 5 . BA , AC , are greater than BD , DC . Again , because the exterior angle of a triangle is greater than the ...
The sides CE , EB , are greater than CD , DB ; but it has been shown that BA , AC , are greater than BE , EC ; much more then 5 . BA , AC , are greater than BD , DC . Again , because the exterior angle of a triangle is greater than the ...
Σελίδα 26
The angle BAC is not less than the angle EDF ; .and it was shown that it is not equal to it ; therefore 3 . The angle BAC is greater than the angle EDF . Wherefore if two triangles , & c . Q.E.D. PROP . XXVI . - THEOREM .
The angle BAC is not less than the angle EDF ; .and it was shown that it is not equal to it ; therefore 3 . The angle BAC is greater than the angle EDF . Wherefore if two triangles , & c . Q.E.D. PROP . XXVI . - THEOREM .
Σελίδα 30
The angle GHF is equal to the angle GKD ; and it was shown that the angle AGK is equal to the angle GHF ; therefore also 3 . AGK is equal to GKD ; and they are alternate angles ; therefore ( I. 27. ) 4 . AB is parallel to CD .
The angle GHF is equal to the angle GKD ; and it was shown that the angle AGK is equal to the angle GHF ; therefore also 3 . AGK is equal to GKD ; and they are alternate angles ; therefore ( I. 27. ) 4 . AB is parallel to CD .
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AB is equal ABC is equal ABCD angle ABC angle ACB angle AGH angle BAC angle BCD angle equal base BC bisected centre circle ABC circumference coincide common demonstrated describe diameter distance divided double draw equal angles exterior angle extremity fall figure four given circle given point given straight line gnomon greater impossible inscribed join less Let ABC Let the straight likewise manner meet opposite angles parallel parallelogram pass pentagon perpendicular point F PROBLEM produced Q.E.D. PROP reason rectangle contained rectilineal figure remaining angle right angles segment semicircle shown side BC sides square of AC straight line AC Take touches the circle triangle ABC twice the rectangle wherefore whole