The Synoptical Euclid; Being the First Four Books of Euclid's Elements of Geometry from the Edition of Dr. Robert Simson ... With Exercises. By S. A. Good ... Second EditionCharles Henry Law, 1854 - 120 σελίδες |
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Σελίδα 7
... straight line AB . Which was to be done . PROP . II . - PROBLEM . From a given point to draw a straight line equal to a given straight line . Let 4 be the given point , and BC the given straight line ; it is required to draw from the point ...
... straight line AB . Which was to be done . PROP . II . - PROBLEM . From a given point to draw a straight line equal to a given straight line . Let 4 be the given point , and BC the given straight line ; it is required to draw from the point ...
Σελίδα 8
... A a straight line AL has been drawn equal to the given straight line BC . Which was to be done . PROP . III . - PROBLEM . From the greater of two given straight lines to cut off a part equal to the less . Let AB and C be the two given ...
... A a straight line AL has been drawn equal to the given straight line BC . Which was to be done . PROP . III . - PROBLEM . From the greater of two given straight lines to cut off a part equal to the less . Let AB and C be the two given ...
Σελίδα 9
... straight line AB upon DE ; 1 . The point B shall coincide with the point E , because AB is equal to DE . And AB coinciding with DE , 2 . AC shall coincide with DF , because the angle BAC is equal to the angle EDF ; wherefore also 3. The ...
... straight line AB upon DE ; 1 . The point B shall coincide with the point E , because AB is equal to DE . And AB coinciding with DE , 2 . AC shall coincide with DF , because the angle BAC is equal to the angle EDF ; wherefore also 3. The ...
Σελίδα 13
... straight line BC upon EF ; 1 . The point C shall coincide with the point F , because BC is equal to EF ; therefore BC coinciding with EF , 2 . BA and AC shall coincide with ED and DF ; for , if the base BC coincide with the base EF ...
... straight line BC upon EF ; 1 . The point C shall coincide with the point F , because BC is equal to EF ; therefore BC coinciding with EF , 2 . BA and AC shall coincide with ED and DF ; for , if the base BC coincide with the base EF ...
Σελίδα 14
... straight line , that is , to divide it into two ... AC , and ( I. 3. ) make CE equal to CD , and upon DE describe ( I. 1. ) the equilateral triangle DFE , and join FC ; the straight line FC drawn from the given point C ' 14 EUCLID'S ELEMENTS ...
... straight line , that is , to divide it into two ... AC , and ( I. 3. ) make CE equal to CD , and upon DE describe ( I. 1. ) the equilateral triangle DFE , and join FC ; the straight line FC drawn from the given point C ' 14 EUCLID'S ELEMENTS ...
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AB is equal AC is equal adjacent angles angle ABC angle ACB angle AGH angle BAC angle BCD angle EDF angle equal base BC bisected circle ABC circumference diameter double draw equal angles equal Constr equal Hyp equal straight lines equal to BC equilateral and equiangular EUCLID'S ELEMENTS exterior angle given circle given point given rectilineal angle given straight line given triangle gnomon greater inscribed interior and opposite less Let ABC Let the straight likewise opposite angles parallel to CD parallelogram pentagon perpendicular point F produced Q.E.D. PROP rectangle AE rectangle contained remaining angle required to describe right angles semicircle side BC square of AC straight line AB straight line AC straight line drawn touches the circle triangle ABC twice the rectangle