The Synoptical Euclid; Being the First Four Books of Euclid's Elements of Geometry from the Edition of Dr. Robert Simson ... With Exercises. By S. A. Good ... Second Edition |
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Σελίδα
... that the principal steps in every demonstration have the conclusions numbered , and printed in separate lines with a different type from the premises ; thus presenting to the eye the substance of the whole in the form of a synopsis ...
... that the principal steps in every demonstration have the conclusions numbered , and printed in separate lines with a different type from the premises ; thus presenting to the eye the substance of the whole in the form of a synopsis ...
Σελίδα 6
The whole is greater than its part . X. Two straight lines cannot inclose a space . XI . All right angles are equal to one another . XII . “ If a straight line meet two straight lines , so as to make the two interior angles on the same ...
The whole is greater than its part . X. Two straight lines cannot inclose a space . XI . All right angles are equal to one another . XII . “ If a straight line meet two straight lines , so as to make the two interior angles on the same ...
Σελίδα 9
The whole triangle ABC shall coincide with the whole triangle DEF and be equal to it ; and the other angles of the one shall coincide with the remaining angles of the other , and be equal to them , viz . 6 . The angle ABC shall be equal ...
The whole triangle ABC shall coincide with the whole triangle DEF and be equal to it ; and the other angles of the one shall coincide with the remaining angles of the other , and be equal to them , viz . 6 . The angle ABC shall be equal ...
Σελίδα 10
And because the whole AF is equal to the whole AG , of which the parts AB , AC are equal , ( Ax . 3. ) 3 . The remainder BF shall be equal to the remainder CG ; and FC was proved to be equal to GB ; therefore the two sides BF , FC are ...
And because the whole AF is equal to the whole AG , of which the parts AB , AC are equal , ( Ax . 3. ) 3 . The remainder BF shall be equal to the remainder CG ; and FC was proved to be equal to GB ; therefore the two sides BF , FC are ...
Σελίδα 31
... was shown to be equal to the angle BAC ; therefore ( Ax . 2. ) 3 . The whole exterior angle ACD is equal to the two interior and opposite angles CAB , ABC ; to each of these equals add the angle ACB ; BOOK I. - PROP . XXXI . XXXII . 31.
... was shown to be equal to the angle BAC ; therefore ( Ax . 2. ) 3 . The whole exterior angle ACD is equal to the two interior and opposite angles CAB , ABC ; to each of these equals add the angle ACB ; BOOK I. - PROP . XXXI . XXXII . 31.
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AB is equal ABC is equal ABCD angle ABC angle ACB angle AGH angle BAC angle BCD angle equal base BC bisected centre circle ABC circumference coincide common demonstrated describe diameter distance divided double draw equal angles exterior angle extremity fall figure four given circle given point given straight line gnomon greater impossible inscribed join less Let ABC Let the straight likewise manner meet opposite angles parallel parallelogram pass pentagon perpendicular point F PROBLEM produced Q.E.D. PROP reason rectangle contained rectilineal figure remaining angle right angles segment semicircle shown side BC sides square of AC straight line AC Take touches the circle triangle ABC twice the rectangle wherefore whole