TABLE. Thermo. Feet. The altitude, thus found, will be to the altitude cor32086-86 rected for the density of the air, inversely, as the 35 87-49 mean height of the barometer, at the two stations, is 40 88.54 to 30 inches; therefore, 45 89-60 50 90 66 55 91-72 60 92.77 65 93-82 70 94.88 75 95 93 80 96-99 RULE.-Multiply the mean height corresponding to the mean temperature of the two barometers (found in the Table) by the tenths of an inch in the difference of the two barometers, and this product by 30; divide this last product by the mean height of the two barometers, and the quotient will be the answer, or height required, with the errour of a few feet only, if the height be less than a mile.* 122. At the first station, suppose the barometer to stand at 29, and the thermometer at 60; at the second station, the barometer at 28, and the thermometer at 40: What is the height of the 2d station or the distance between the two places of observation? Barometer. sum 28.5-mean height of the two barometers. 29 28 Sv Difference 1=10 tenths of an inch. Thermometer. First station =60 Second station =40 100 50 mean height of the two thermometers, against which, in the Table you will find 90-66, the mean temperature of the two barometers. Now, according to the rule 90-66×10×30-÷ 28.5-954-3 feet, the Answer, nearly. Leth: mean height of the barometer at its two stations, (or of two barometers, one at each station) in inches; d= difference of the two barometers in tenths of an inch; and n = number from the Table answering to the mean tem30dn perature of the two thermometers accompanying the barometer, then altitude required nearly. the h The Act of Congress of April 29, 1816, regulating the currency within the United States of the gold coins of Great Britain, France, &c. enacted, 27 grs. That, of the gold coins of Great Britain and Portugal, 100 cents, or 1 pwt.88% cents; do. 87 do. do. 84 do. do. Of France, 27 grs. Spain, 231grs. do. Crowns of France, weighing 449grs.110cents, or loz.=117c. Five franc pieces, weighing 386grs. 93.3 cts. or 1oz.=116 cts. The Spanish dollar, weighing not less than 415grs.=100 cents. The Federal dollar is to be of the weight and purity of the Spanish dollar; but, it is to weigh 416grs. and to contain 3714grs. of pure silver. The pound Sterling of England is $4.44 in the United States. The dollar is reckoned, therefore, at four shillings and six pence sterling; but in 1820, four shillings and six pence of English silver coin contained only 3634grs. of pure silver, being 3grs. less than is contained in the Federal dollar. One pound Troy weight of Standard Gold in England, contains 5280grs. of pure gold, and is coined into £46 14s. 6d. or 11214 pence. Hence a pound sterling contains 113 0016grs. of pure gold. The Eagle contains 247.5grs. of pure gold, and hence the pound sterling is worth in gold $4 56-572, and hence the dollar is worth in English gold 48. 4.5656d. One pound Troy of Standard silver in England contains 5328grs. of pure silver, and is coined into 66 shillings or 792 pence. As the dollar contains 3714grs. of pure silver, the dollar is worth in English silver 4s. 7·1858d. In a pound sterling there is 1614-545grs. of pure silver, which is equal in silver to $4.34 8943. Taking the mean of the values of the dollar and the pound sterling in gold and silver, The value of the dollar is 4s 5.8757d. sterling. And the value of the pound sterling is $4.45-7331. This mean value of the dollar and the pound sterling is very near the values at which they are commonly estimated. [See Report of the Secretary of State upon Weights and Measures," appendix C. to Congress, Feb. 1821.] The standard price of gold in England, is £3 17s. 10d. an oz. and of silver 5s. 2d. an oz. The standard weight of the English guinea is 5pwt. 93grs.; but it usually weighs 5pwt. 8grs. The standard coin of France is to contain one tenth of alloy, and the standard value of gold to silver is 15 to 1.. The following Tables are calculated according to the value of Foreign Gold established by act of Congress, April 29, 1816. |