Intermediate Arithmetic on the Inductive Method: With Parallel Mental and Written ExercisesF.F. Hansell & Bro., 1885 - 224 σελίδες |
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Σελίδα 64
... cost ? 46. A pole is 43 feet in the air , 19 feet in the earth , and 18 feet in the water . How long is the pole ? 47. A lad , having spent 43 cents , finds he has 59 cents left . How much had he at first ? 48. How many are 43 and 22 ...
... cost ? 46. A pole is 43 feet in the air , 19 feet in the earth , and 18 feet in the water . How long is the pole ? 47. A lad , having spent 43 cents , finds he has 59 cents left . How much had he at first ? 48. How many are 43 and 22 ...
Σελίδα 68
... cost if each horse cost $ 150 ? 70. PARALLEL PROBLEMS . Ans . ? NOTE . In these and in subsequent parallel problems the men- tal , denoted by m , involve the same principles as the succeed- g written problem or problems , and are ...
... cost if each horse cost $ 150 ? 70. PARALLEL PROBLEMS . Ans . ? NOTE . In these and in subsequent parallel problems the men- tal , denoted by m , involve the same principles as the succeed- g written problem or problems , and are ...
Σελίδα 69
... cost me ; what did the hog cost ? 4. By selling a farm for $ 1305 I lost $ 960.50 ; what did the farm cost me ? Ans . $ 2265.50 . 5.m James spent $ 8 for pants , $ 9 for a coat , and $ 5 for a vest ; how much did he spend in all ? 6. A ...
... cost me ; what did the hog cost ? 4. By selling a farm for $ 1305 I lost $ 960.50 ; what did the farm cost me ? Ans . $ 2265.50 . 5.m James spent $ 8 for pants , $ 9 for a coat , and $ 5 for a vest ; how much did he spend in all ? 6. A ...
Σελίδα 78
... $ 15 , and paid the balance in cash ; how much cash did he pay ? 35. I gave a horse worth $ 80 for a cow and $ 18 in money ; how much did the cow cost me ? 36. William had 42 oranges and gave 9 to Mary 78 Intermediate Arithmetic .
... $ 15 , and paid the balance in cash ; how much cash did he pay ? 35. I gave a horse worth $ 80 for a cow and $ 18 in money ; how much did the cow cost me ? 36. William had 42 oranges and gave 9 to Mary 78 Intermediate Arithmetic .
Σελίδα 83
... cost than the buggy ? Ans . $ 68.65 . 42. A farmer bought a wagon for $ 113 , and gave in exchange a cow worth $ 43.75 , and the balance in cash ; how much was the balance ? Ans . $ 69.25 . 43. Mount Sorata , a peak of the Andes , is ...
... cost than the buggy ? Ans . $ 68.65 . 42. A farmer bought a wagon for $ 113 , and gave in exchange a cow worth $ 43.75 , and the balance in cash ; how much was the balance ? Ans . $ 69.25 . 43. Mount Sorata , a peak of the Andes , is ...
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Intermediate Arithmetic on the Inductive Method, With Parallel Mental and ... J. W. Nicholson Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2016 |
Intermediate Arithmetic on the Inductive Method, with Parallel Mental and ... J. W. Nicholson Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2018 |
Συχνά εμφανιζόμενοι όροι και φράσεις
9 leaves acres annex apiece apples barrels bers birds boys bushels calling the results cents ciphers common denominator common fraction contain Copy and read Count cows cubic decimal denoted dimes Divide dividend Division dollars equal EXPLANATION.-Since feet fifths fingers fourths fractional unit frogs gallons girls hats Hence hogs horses hundred hundred twenty-seven hundredths hunds II.-When improper fraction inches INDUCTIVE EXERCISES less lowest terms marbles measure MENTAL EXERCISES miles minuend mixed number multiplicand multiply OPERATION peaches pints pounds prime factors proper fraction pupil quarts QUESTIONS FOR REVIEW quotient Reduce remainder RULE.-I RULE.-Multiply sheep simple fraction sold soldiers square miles subtract subtrahend TABLE taken tenths thirds thousand thousandths weighs whole number wide write WRITTEN EXERCISES yards cost yards of cloth а а а
Δημοφιλή αποσπάσματα
Σελίδα 132 - Multiplying or dividing both terms of a fraction by the same number does not alter the value of the fraction.
Σελίδα 111 - V. If any partial dividend will not contain the divisor, place a cipher in the quotient, and bring down the next figure of the dividend, and divide as before.
Σελίδα 166 - Place the multiplier under the multiplicand, disregarding the position of the decimal points. Multiply as in whole numbers, and in the product point off as many decimal places as there are decimal places in both multiplier and multiplicand, prefixing ciphers if necessary. EXAMPLES FOR PRACTICE.
Σελίδα 167 - When the decimal places in the divisor exceed those in the dividend, make them equal by annexing ciphers to the dividend, and the quotient will be a whole number.
Σελίδα 108 - Multiply the integer of the quotient by the divisor, and to the product add the remainder, if any ; and the result will equal the dividend, if the work is right.
Σελίδα 113 - Place the sum down as in the last example, then mark off from the right of the dividend as many figures as there are ciphers in the divisor...
Σελίδα 111 - Find how many times the divisor is contained in the LEAST number of the left hand figures of the dividend that will contain it, and place the quotient at the right of the dividend.
Σελίδα 97 - The dividend is the number to be divided. The divisor is the number by which we divide.
Σελίδα 82 - Multiplication is the process of taking one number as many times as there are units in another.
Σελίδα 91 - Multiply the multiplicand by each figure of the multiplier successively, beginning with the unit, figure, and write the first figure of each partial product under the figure of the multiplier used, writing down and carrying as in addition.