Current N. 73° R.

Var. 19 L.

N. 54 R. B

C

FIG. 78.

D. lat. 2° 38' S.

Lat. in 47° 19' N.

2)97° 16'

Mid. lat. 48° 38'
Dep. 41.6

D. long. 62.95

...

D. long. 1° 3' E.

Long in 4° 9′ W.

sec 10.179880

log 1.619093

log 1.798973

In Fig. 78 scale 1 inch = 100 miles, ABC represents meridian.

NOTE 1.-The D. long. can also be found by inspection thus: Take the
mid. lat. as a course and find dep. in D. lat. column; the dist. corresponding
is the D. long.

NOTE 2. When course and leeway are in "points," it is most convenient to
allow the leeway before changing points into degrees, then apply the correction.
NOTE 3.-To calculate course and distance made good.
D. lat. 158 3 S., dep. 41.6 E.

158.3

In triangle ABC, Ĉ = 90, AC = 158.3, BC = 41.6.

.. AB

=

FIG. 79.

41.6 log = 11.619093 158.3 log = 2.199481

AC x sec A

2.199481

sec 10.014501

163.7 log

= 2.213982

Course S. 14° 43′ 26′′ E., distance 163.7 miles.

Correct the courses for Deviation, Variation, and Leeway, and find the course and distance from the given point, and the Latitude and Longitude in.

Find the course and distance made good; Latitude and Longitude of the ship.

Correct the courses for Deviation, Variation, and Leeway, and find the course and distance from the given point, and the Latitude and Longitude in.

Correct the courses for Deviation, Variation, and Leeway, and find the course and distance from the given point, and the Latitude and Longitude in.

The position by observation was found to be lat. 30° 25' N., long. 133 7' E. Find the set and drift of the current.

The ship by observation was found in lat. 51° 59' N., long. 178° 5' W. Find set and drift of current.