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altitude angle axis base called centimeters chord circle circular measure circumference circumscribed common cone congruent constant contains corresponding cube cubic centimeters cubic meters cylinder diagonals diameter difference distance divided double draw edges ends equal equilateral equivalent Exam expression faces figure Find the area Find the ratio find the volume Formula four frustum Given gives half Hence inscribed intersection joining lateral edges length less limit lune mantel mass mean meters long midpoint Multiply opposite parabola parallel parallel sides passing perimeter perpendicular plane polygon polyhedron prism prismatoid prismoid Proof Prove pyramid quader quadrilateral radii radius rectangle right-angled Rule sector segment sides similar slant height solid sphere spherical square meters straight line surface symmetric tangents tetrahedron third trapezoid triangle twice unit variable vertex vertices whole
Σελίδα 224 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Σελίδα 109 - COR. 2. The volume of any truncated triangular prism is equal to the product of its right section by one third the sum of its lateral edges.
Σελίδα 34 - From half the sum of the three sides, subtract each side separately; multiply the half sum and the three remainders together, and the square root of the product will be the area required.
Σελίδα 86 - ... discussion has been carried on, the principal point discussed being the claims of the gramme, the metre, and the second, as against the gramme, the centimetre, and the second, — the former combination having an advantage as regards the simplicity of the name metre, while the latter combination has the advantage of making the unit of mass practically identical with the mass of unit-volume of water — in other words, of making the value of the density of water practically equal to unity.
Σελίδα 20 - The perimeters of regular polygons of the same number of sides have the same ratio as their radii or as their apothems. ADB A' D' B' Hyp. P and P' are the perimeters of two regular polygons having the radii OA and O'A', and the apothems OD and O'D', respectively. To prove P:P' = OA: O'A