Second section and division.

Here 32.3 × 32.3 = 1043.29, the square of the diameter; and 1043.29 12.96 80.50, the gross area. One-fifth of this area is = 16.10; then 80.50

16.10 64.40, the net area of the section; and 64.40 x 10 644.00 pounds, the net content of the division.

Third section and division. Here 29.5 × 29.5 = 870.25, diameter; and 870.25 area. One-fifth of this area is

the square of the 12.96 67.14, the gross 13.42; then 67.14

13.42 = 53.72, the net area of the section; and 53.72 × 10 = 537.2, the net area of the section; and 53.72 × 10 = 537.20 pounds, the net content of the division.

area.

Fourth seetion and division.

Here 25.5 x 25.5 = 650.25, the square of the diameter; and 650.25 12.96 50.17, the gross One-fifth of this area is = 10.03; then 50.17 10.03 40.14, the net area of the section; and 40.14 X 7 = 2809.8 pounds, the net content of the division. Note The net area of the last section is multiplied by 7, in order to make an allowance of 3 inches at the bottom of the vessel. Areas and contents collected and reduced into hundred weights, quarters, and pounds.

A TABLE

Shewing the Method of inching the Pot, given in thi

THE METHOD OF ESTIMATING THE WEIGHT OF CANDLES, BOTH BY THE PEN AND THE SLIDING RULE.

PROBLEM.

Given the number of candles in one pound, the number on one rod, and the number of rods, to find the whole weight in pounds.

SECTION VII.

The Method of finding the Areas and Contents of Vessels, in Irish Malt Bushels, and Liquid Gallons; also the Process of reducing Irish to English Measure, and vice versa. Likewise Specific Gravity, or the Method of finding the Magnitude of a Body from its Weight, or the Weight of a Body from its Magnitude; also the Method of estimating the Tonnage of Ships according to the Parliamentary Rules.

IRISH MEASURES..

PROBLEM I.

To find the area and content of any angular vessel, in Irish malt bushels, and liquid gallons.

EXAM. 2.

Here 96.8 x 63.6 6156.48, the area of the base in square inches; and 6156.48 ÷ 2178 = 2.826, the area of the base, in Irish malt bushels; also, 6156.48 217.6 = 28.292, the area in Irish liquid gallons; then 2.826 × 55.4 = 156,5604, the content of the vessel, in Irish malt bushels; and 28.292 × 55.4 = 1567.3768, the content in Irish liquid gallons.

PROBLEM II.

To find the area and content of a cylindrical vessel, in Irish malt bushels, and liquid gallons.

EXAM. 2.

Here 82.4 × 82.46789.76, the square of the diameter; and 6789.76 ÷ 2773.12.448, the area in Irish malt bushels; also, 6789.76 ÷ 277.05 = 24.507, the area in Irish liquid gallons; then 2.448 x 52.6 128.7648, the content of the vessel, in Irish malt bushels; and 24.507 × 52.6 = 1289.0682, the content in Irish liquid gallons.

PROBLEM III.

To reduce Irish measure to English measure.

EXAM. 3.

Here 1,0128 x 2685 2719.368, English malt bushels.

EXAM. 4.

Here .9419 x 2864 = 2697.6016, English wine gallons.

EXAM. 5.

Here 56 × 32 = 1792, the number of gallons, according to the gauge in Ireland; and .7716 × 1792 =1382.7072, the number of English ale gallons; then, 1382.7 36 38 barrels, 14.7 gallons, the answer required.