Elements of Geometry: Containing the First Six Books of Euclid, with a Supplement on the Quadrature of the Circle, and the Geometry of Solids ; to which are Added, Elements of Plane and Spherical TrigonometryW.E. Dean, 1836 - 311 σελίδες |
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Σελίδα 12
... equal to the angle CGA , by equal additions , the sum of the two angles BAG , CAG , is equal to the sum of the two angles BGA , CGA , ( Ax . 2. ) that is , the whole an- gle BAC equal to the whole angle BGC . Since , then , the two ...
... equal to the angle CGA , by equal additions , the sum of the two angles BAG , CAG , is equal to the sum of the two angles BGA , CGA , ( Ax . 2. ) that is , the whole an- gle BAC equal to the whole angle BGC . Since , then , the two ...
Σελίδα 20
... equal to the angle GHD ; and they A E G B are the alternate angles ; therefore AB is parallel ( 19.1 . ) to CD . Again , because the angles BGH , GHD are equal ( by Hyp . ) to two right angles , C H D and AGH , BGH , are also equal ...
... equal to the angle GHD ; and they A E G B are the alternate angles ; therefore AB is parallel ( 19.1 . ) to CD . Again , because the angles BGH , GHD are equal ( by Hyp . ) to two right angles , C H D and AGH , BGH , are also equal ...
Σελίδα 121
... angle DEF is equal ( 5. 1. ) to the angle GEF , and the other angles to . the other angles , which are subtended by the equal sides ( 1. 1. ) . Wherefore the angle DFE is equal to the angle GFE , and EDF to EGF : and because the angle DEF ...
... angle DEF is equal ( 5. 1. ) to the angle GEF , and the other angles to . the other angles , which are subtended by the equal sides ( 1. 1. ) . Wherefore the angle DFE is equal to the angle GFE , and EDF to EGF : and because the angle DEF ...
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ABC is equal ABCD adjacent angles altitude angle ABC angle ACB angle BAC angles equal arc AC base BC bisected centre chord circle ABC circumference cosine cylinder definition demonstrated diameter divided equal and similar equal angles equiangular equilateral equilateral polygon equimultiples Euclid exterior angle fore four right angles given straight line greater Hence hypotenuse inscribed join less Let ABC Let the straight magnitudes meet multiple opposite angle parallel parallelogram parallelopiped perpendicular polygon prism PROP proposition quadrilateral radius ratio rectangle contained rectilineal figure remaining angle right angled triangle SCHOLIUM segment semicircle shewn side BC sine solid angle spherical angle spherical triangle square straight line BC THEOR third touches the circle triangle ABC triangle DEF wherefore