Elements of Geometry: Containing the First Six Books of Euclid, with a Supplement on the Quadrature of the Circle, and the Geometry of Solids ; to which are Added, Elements of Plane and Spherical TrigonometryW.E. Dean, 1836 - 311 σελίδες |
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Σελίδα 15
... side AB is equal to the side AD ; therefore the angle ABD is like- D B C wise greater than the angle ACB ; wherefore ... BC ; and AB , BC greater than AC ; and BC , CA greater than AB . D A Produce BA to the point D , and make AD ...
... side AB is equal to the side AD ; therefore the angle ABD is like- D B C wise greater than the angle ACB ; wherefore ... BC ; and AB , BC greater than AC ; and BC , CA greater than AB . D A Produce BA to the point D , and make AD ...
Σελίδα 16
... BC is less than BA + AC , or BA + AC > BC . PROP . XIV . THEOR . If from the ends of one side of a triangle , there be drawn two straight lines to a point within the triangle , these two lines shall be less than the other two sides of ...
... BC is less than BA + AC , or BA + AC > BC . PROP . XIV . THEOR . If from the ends of one side of a triangle , there be drawn two straight lines to a point within the triangle , these two lines shall be less than the other two sides of ...
Σελίδα 26
... side BC , which is adjacent to these equal angles , common to the two triangles ; therefore their other sides are equal , each to each , and the third angle of the one to the third angle of the other ( Th . 2. ) ; viz . the side AB to the ...
... side BC , which is adjacent to these equal angles , common to the two triangles ; therefore their other sides are equal , each to each , and the third angle of the one to the third angle of the other ( Th . 2. ) ; viz . the side AB to the ...
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ABC is equal ABCD adjacent angles altitude angle ABC angle ACB angle BAC angles equal arc AC base BC bisected centre chord circle ABC circumference cosine cylinder definition demonstrated diameter divided equal and similar equal angles equiangular equilateral equilateral polygon equimultiples Euclid exterior angle fore four right angles given straight line greater Hence hypotenuse inscribed join less Let ABC Let the straight magnitudes meet multiple opposite angle parallel parallelogram parallelopiped perpendicular polygon prism PROP proposition quadrilateral radius ratio rectangle contained rectilineal figure remaining angle right angled triangle SCHOLIUM segment semicircle shewn side BC sine solid angle spherical angle spherical triangle square straight line BC THEOR third touches the circle triangle ABC triangle DEF wherefore