Elements of GeometryHilliard and Metcalf, 1825 - 224 σελίδες |
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Αποτελέσματα 1 - 5 από τα 100.
Σελίδα 7
... hence , x + x + b + x + b + c = ɑ . This expression , which is so simple , may be still further abridged ; for since it appears that x enters three times into the number to be divided and b twice , instead of x + x + x , I shall write 3 ...
... hence , x + x + b + x + b + c = ɑ . This expression , which is so simple , may be still further abridged ; for since it appears that x enters three times into the number to be divided and b twice , instead of x + x + x , I shall write 3 ...
Σελίδα 15
... hence conclude , that Let there be the equation bc x = - a ах - bx + c x = ac bc , which contains three terms involving the unknown quantity . Since a x , b x , cx , represent the products respectively of x by the quantities a , b , and ...
... hence conclude , that Let there be the equation bc x = - a ах - bx + c x = ac bc , which contains three terms involving the unknown quantity . Since a x , b x , cx , represent the products respectively of x by the quantities a , b , and ...
Σελίδα 65
... Hence the equations 7 X 2 = - -- 14 , 5 X 2 = - 10 . - 60+ 7y = 46 , and 40+ 5 y = 30 , become respectively 60 14 46 , and 40 10 = 30 , - - and are verified , not by adding the two parts of the first member , but in reality by ...
... Hence the equations 7 X 2 = - -- 14 , 5 X 2 = - 10 . - 60+ 7y = 46 , and 40+ 5 y = 30 , become respectively 60 14 46 , and 40 10 = 30 , - - and are verified , not by adding the two parts of the first member , but in reality by ...
Σελίδα 99
... hence arises this new numerical question ; to find a number , which , multiplied by itself , will give a product equal to a proposed number ; or , which is the same thing , from the second power of a number , to retrace our steps to the ...
... hence arises this new numerical question ; to find a number , which , multiplied by itself , will give a product equal to a proposed number ; or , which is the same thing , from the second power of a number , to retrace our steps to the ...
Σελίδα 103
... hence the greatest square contained in 2237 , will be the square of 47 , or that of the tens of the root . In order to find these tens , we must evidently proceed , as if we had to extract the square root of 2237 only ; but instead of ...
... hence the greatest square contained in 2237 , will be the square of 47 , or that of the tens of the root . In order to find these tens , we must evidently proceed , as if we had to extract the square root of 2237 only ; but instead of ...
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Άλλες εκδόσεις - Προβολή όλων
Συχνά εμφανιζόμενοι όροι και φράσεις
a² b³ algebraic Algebraic Quantities Arith arithmetic becomes binomial changing the signs coefficient common divisor consequently contains courier cube root decimal deduce denominator denoted divided dividend division employed entire number enunciation equa evident example exponent expression extract the root figures follows formula fraction given in art given number gives greater greatest common divisor last term letters logarithm manner method multiplicand multiplied negative number of arrangements observed obtain operation perfect square polynomials preceding article proposed equation proposed number quan question quotient radical quantities radical sign reduced remainder represented resolve result rule given second degree second member second term simple quantities square root subtract suppose taken tens third tion tities units unity unknown quantity vulgar fractions whence whole numbers
Δημοφιλή αποσπάσματα
Σελίδα 9 - If two triangles have the three sides of the one equal to the three sides of the other, each to each, the triangles are congruent.
Σελίδα 44 - Divide the first term of the dividend by the first term of the divisor, and write the result as the first term of the quotient. Multiply the whole divisor by the first term of the quotient, and subtract the product from the dividend.
Σελίδα 63 - The areas of two triangles which have an angle of the one equal to an angle of the other are to each other as the products of the sides including the equal angles. A D A' Hyp. In triangles ABC and A'B'C', To prove AABC A A'B'C' A'B' x A'C ' Proof. Draw the altitudes BD and B'D'.
Σελίδα 101 - Which proves that the square of a number composed of tens and units, contains the square of the tens plus twice the product of the tens by the units, plus the square of the units.
Σελίδα 8 - Any side of a triangle is less than the sum of the other two sides...
Σελίδα 122 - ... is negative in the second member, and greater than the square of half the coefficient of the first power of the unknown quantity, this equation can have only imaginary roots.
Σελίδα 180 - CD, &c., taken together, make up the perimeter of the prism's base : hence the sum of these rectangles, or the convex surface of the prism, is equal to the perimeter of its base multiplied by its altitude.
Σελίδα 54 - The sum of the squares on the sides of a parallelogram is equal to the sum of the squares on the diagonals.
Σελίδα 185 - The convex surface of a cone is equal to the circumference of the base multiplied by half the slant height.
Σελίδα 164 - If two triangles have two sides and the inchtded angle of the one respectively equal to two sides and the included angle of the other, the two triangles are equal in all respects.