Elements of GeometryHilliard and Metcalf, 1825 - 224 σελίδες |
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Αποτελέσματα 1 - 5 από τα 81.
Σελίδα 51
... meet with in numbers , and this is , that the first term of the divisor will not exactly divide the first term of the dividend , on account of the factors 4 and b in the one , which are not in the other . But the letter b being common ...
... meet with in numbers , and this is , that the first term of the divisor will not exactly divide the first term of the dividend , on account of the factors 4 and b in the one , which are not in the other . But the letter b being common ...
Σελίδα 69
... meet each other at the same time from two cities , the distance of which is given ; we know how many miles ( a ) each travels per hour , and we inquire at what point of the route between the two cities they will meet . To render the ...
... meet each other at the same time from two cities , the distance of which is given ; we know how many miles ( a ) each travels per hour , and we inquire at what point of the route between the two cities they will meet . To render the ...
Σελίδα 70
... meet . 65. I will now suppose , that the two couriers proceed in the same direction , and that the one who sets out from A is pursu- ing the one who sets out from B , and who is travelling toward the same point C , placed beyond B ...
... meet . 65. I will now suppose , that the two couriers proceed in the same direction , and that the one who sets out from A is pursu- ing the one who sets out from B , and who is travelling toward the same point C , placed beyond B ...
Σελίδα 77
... meet with an expression which becomes , it is proper , before pro- nouncing upon its value , to see if the numerator and denominator have not a common factor , which becoming nothing , renders the two terms at the same time equal to ...
... meet with an expression which becomes , it is proper , before pro- nouncing upon its value , to see if the numerator and denominator have not a common factor , which becoming nothing , renders the two terms at the same time equal to ...
Σελίδα 81
... meet between A and C. Thus , this case is similar to the first of those of art . 74 , where it is sufficient to change a - cd into cd a , in order to obtain the value , which m has according to the above equation . * - 76. The problem ...
... meet between A and C. Thus , this case is similar to the first of those of art . 74 , where it is sufficient to change a - cd into cd a , in order to obtain the value , which m has according to the above equation . * - 76. The problem ...
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Άλλες εκδόσεις - Προβολή όλων
Συχνά εμφανιζόμενοι όροι και φράσεις
a² b³ algebraic Algebraic Quantities Arith arithmetic becomes binomial changing the signs coefficient common divisor consequently contains courier cube root decimal deduce denominator denoted divided dividend division employed entire number enunciation equa evident example exponent expression extract the root figures follows formula fraction given in art given number gives greater greatest common divisor last term letters logarithm manner method multiplicand multiplied negative number of arrangements observed obtain operation perfect square polynomials preceding article proposed equation proposed number quan question quotient radical quantities radical sign reduced remainder represented resolve result rule given second degree second member second term simple quantities square root subtract suppose taken tens third tion tities units unity unknown quantity vulgar fractions whence whole numbers
Δημοφιλή αποσπάσματα
Σελίδα 9 - If two triangles have the three sides of the one equal to the three sides of the other, each to each, the triangles are congruent.
Σελίδα 44 - Divide the first term of the dividend by the first term of the divisor, and write the result as the first term of the quotient. Multiply the whole divisor by the first term of the quotient, and subtract the product from the dividend.
Σελίδα 63 - The areas of two triangles which have an angle of the one equal to an angle of the other are to each other as the products of the sides including the equal angles. A D A' Hyp. In triangles ABC and A'B'C', To prove AABC A A'B'C' A'B' x A'C ' Proof. Draw the altitudes BD and B'D'.
Σελίδα 101 - Which proves that the square of a number composed of tens and units, contains the square of the tens plus twice the product of the tens by the units, plus the square of the units.
Σελίδα 8 - Any side of a triangle is less than the sum of the other two sides...
Σελίδα 122 - ... is negative in the second member, and greater than the square of half the coefficient of the first power of the unknown quantity, this equation can have only imaginary roots.
Σελίδα 180 - CD, &c., taken together, make up the perimeter of the prism's base : hence the sum of these rectangles, or the convex surface of the prism, is equal to the perimeter of its base multiplied by its altitude.
Σελίδα 54 - The sum of the squares on the sides of a parallelogram is equal to the sum of the squares on the diagonals.
Σελίδα 185 - The convex surface of a cone is equal to the circumference of the base multiplied by half the slant height.
Σελίδα 164 - If two triangles have two sides and the inchtded angle of the one respectively equal to two sides and the included angle of the other, the two triangles are equal in all respects.