Elements of GeometryHilliard and Metcalf, 1825 - 224 σελίδες |
Αναζήτηση στο βιβλίο
Αποτελέσματα 1 - 5 από τα 67.
Σελίδα 22
... radius or semi- diameter , and every straight line , as AB , which passes through the centre and is terminated each way by the circumference , is called a diameter . By the definition of a circle the radii are all equal , and all the ...
... radius or semi- diameter , and every straight line , as AB , which passes through the centre and is terminated each way by the circumference , is called a diameter . By the definition of a circle the radii are all equal , and all the ...
Σελίδα 24
... radius CD will fall upon the radius OG , and the point D upon G , therefore the arc AMD is equal to the arc ENG . THEOREM . 103. In the same circle , or in equal circles , if the arc be less than half a circumference , the greater arc ...
... radius CD will fall upon the radius OG , and the point D upon G , therefore the arc AMD is equal to the arc ENG . THEOREM . 103. In the same circle , or in equal circles , if the arc be less than half a circumference , the greater arc ...
Σελίδα 26
... radius OB , will pass through the three points A , B , C. It is thus proved , that the circumference of a circle may be made to pass through any three given points , which are not in the same straight line ; it remains to show , that ...
... radius OB , will pass through the three points A , B , C. It is thus proved , that the circumference of a circle may be made to pass through any three given points , which are not in the same straight line ; it remains to show , that ...
Σελίδα 27
... radius AC , is a tangent to the circumference . Demonstration . Since every oblique line CE is greater than the ... radius CA , and with respect to this new tangent the radius CA would be an oblique line , and the perpendicular let fall ...
... radius AC , is a tangent to the circumference . Demonstration . Since every oblique line CE is greater than the ... radius CA , and with respect to this new tangent the radius CA would be an oblique line , and the perpendicular let fall ...
Σελίδα 28
... radius CH per- pendicular to the chord MP , it will also be perpendicular to its parallel NQ ( 64 ) , and the point H will be at the same time the middle of the arc MHP and of NHQ ( 105 ) ; whence the arc MHHP , and the arc NH = HQ ...
... radius CH per- pendicular to the chord MP , it will also be perpendicular to its parallel NQ ( 64 ) , and the point H will be at the same time the middle of the arc MHP and of NHQ ( 105 ) ; whence the arc MHHP , and the arc NH = HQ ...
Περιεχόμενα
1 | |
2 | |
8 | |
14 | |
23 | |
30 | |
46 | |
53 | |
160 | |
168 | |
170 | |
174 | |
180 | |
186 | |
190 | |
192 | |
59 | |
66 | |
81 | |
91 | |
98 | |
99 | |
105 | |
111 | |
117 | |
123 | |
131 | |
136 | |
149 | |
150 | |
13 | |
27 | |
36 | |
8 | |
22 | |
44 | |
77 | |
86 | |
220 | |
Άλλες εκδόσεις - Προβολή όλων
Συχνά εμφανιζόμενοι όροι και φράσεις
a² b³ algebraic Algebraic Quantities Arith arithmetic becomes binomial changing the signs coefficient common divisor consequently contains courier cube root decimal deduce denominator denoted divided dividend division employed entire number enunciation equa evident example exponent expression extract the root figures follows formula fraction given in art given number gives greater greatest common divisor last term letters logarithm manner method multiplicand multiplied negative number of arrangements observed obtain operation perfect square polynomials preceding article proposed equation proposed number quan question quotient radical quantities radical sign reduced remainder represented resolve result rule given second degree second member second term simple quantities square root subtract suppose taken tens third tion tities units unity unknown quantity vulgar fractions whence whole numbers
Δημοφιλή αποσπάσματα
Σελίδα 9 - If two triangles have the three sides of the one equal to the three sides of the other, each to each, the triangles are congruent.
Σελίδα 44 - Divide the first term of the dividend by the first term of the divisor, and write the result as the first term of the quotient. Multiply the whole divisor by the first term of the quotient, and subtract the product from the dividend.
Σελίδα 63 - The areas of two triangles which have an angle of the one equal to an angle of the other are to each other as the products of the sides including the equal angles. A D A' Hyp. In triangles ABC and A'B'C', To prove AABC A A'B'C' A'B' x A'C ' Proof. Draw the altitudes BD and B'D'.
Σελίδα 101 - Which proves that the square of a number composed of tens and units, contains the square of the tens plus twice the product of the tens by the units, plus the square of the units.
Σελίδα 8 - Any side of a triangle is less than the sum of the other two sides...
Σελίδα 122 - ... is negative in the second member, and greater than the square of half the coefficient of the first power of the unknown quantity, this equation can have only imaginary roots.
Σελίδα 180 - CD, &c., taken together, make up the perimeter of the prism's base : hence the sum of these rectangles, or the convex surface of the prism, is equal to the perimeter of its base multiplied by its altitude.
Σελίδα 54 - The sum of the squares on the sides of a parallelogram is equal to the sum of the squares on the diagonals.
Σελίδα 185 - The convex surface of a cone is equal to the circumference of the base multiplied by half the slant height.
Σελίδα 164 - If two triangles have two sides and the inchtded angle of the one respectively equal to two sides and the included angle of the other, the two triangles are equal in all respects.