A Treatise on Practical Surveying: Which is Demonstrated from Its First Principles : Wherein Every Thing that is Useful and Curious in that Art, is Fully Considered and ExplainedF. Lucas, jun. and Cushing & Jewett, J. Robinson printer, 1822 - 326 σελίδες |
Αναζήτηση στο βιβλίο
Αποτελέσματα 1 - 5 από τα 18.
Σελίδα 29
... parallelograms : thus ABCD is a parallelogram . fig . 3. 17. and fig . 18. 19 . [ see fig . 3 . page 25. ] ن 30. A parallelogram whose sides are all equal and angles GEOMETRY . 29.
... parallelograms : thus ABCD is a parallelogram . fig . 3. 17. and fig . 18. 19 . [ see fig . 3 . page 25. ] ن 30. A parallelogram whose sides are all equal and angles GEOMETRY . 29.
Σελίδα 30
... parallelogram whose opposite sides are equal and angles right , is called a rectangle or an oblong , as ABCD , fig . 3 . 32. A rhombus is a parallelogram of equal sides , and has its angles ob- lique , as fig . 18 . 33. A rhomboides is ...
... parallelogram whose opposite sides are equal and angles right , is called a rectangle or an oblong , as ABCD , fig . 3 . 32. A rhombus is a parallelogram of equal sides , and has its angles ob- lique , as fig . 18 . 33. A rhomboides is ...
Σελίδα 44
... parallelogram . Cor . 3. It is hence also plain , that the opposite sides of a parallelogram are equal ; for it has been proved that ABCD being a parallelogram , AB will be - CD and AD - BC . THEOREM XIII . All parallelograms on the ...
... parallelogram . Cor . 3. It is hence also plain , that the opposite sides of a parallelogram are equal ; for it has been proved that ABCD being a parallelogram , AB will be - CD and AD - BC . THEOREM XIII . All parallelograms on the ...
Σελίδα 45
... parallelogram EFGH = BDEF . Wherefore ABCD = BDEF = EFHG . Q. E. D .. Cor . Hence it is plain that triangles on the ... parallelogram BKLH ( by the same ; ) therefore half the square ABDE is equal to half the parallelogram BKLH , and the ...
... parallelogram EFGH = BDEF . Wherefore ABCD = BDEF = EFHG . Q. E. D .. Cor . Hence it is plain that triangles on the ... parallelogram BKLH ( by the same ; ) therefore half the square ABDE is equal to half the parallelogram BKLH , and the ...
Σελίδα 46
... parallelogram KCLM . So ABDE + ACGF the sum of the squares , = BKLH + KCML , the sum of the two parallelograms or square BCMH ; therefore the sum of the squares on AB and AC is equal to the square on BC . Q. E. D. Cor , 1. Hence the ...
... parallelogram KCLM . So ABDE + ACGF the sum of the squares , = BKLH + KCML , the sum of the two parallelograms or square BCMH ; therefore the sum of the squares on AB and AC is equal to the square on BC . Q. E. D. Cor , 1. Hence the ...
Άλλες εκδόσεις - Προβολή όλων
A Treatise of Practical Surveying: Which is Demonstrated From Its First ... Robert Gibson Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2021 |
Συχνά εμφανιζόμενοι όροι και φράσεις
20 perches ABCD acres altitude Answer base bearing blank line centre chains and links chord circle circumferentor Co-secant co-sine Co-tang column compass contained cyphers decimal decimal fraction difference Dist divided divisor draw east edge EXAMPLE feet field-book figures four-pole chains given angle half the sum height Hence hypothenuse inches instrument latitude length logarithm measure meridian distance multiplied needle number of degrees object off-sets opposite parallel parallelogram perpendicular piece of ground plane polygon Portmarnock PROB proportion protractor quotient radius right angles right line scale of equal SCHOLIUM secant second station sect semicircle side sights sine square root stationary distance stationary line sun's suppose survey taken tang tangent thence theo theodolite THEOREM thro triangle ABC trigonometry true amplitude true azimuth two-pole chains vane variation whence