An elementary treatise on MechanicsMacmillan, 1863 - 374 σελίδες |
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Αποτελέσματα 1 - 5 από τα 64.
Σελίδα v
... triangle of forces , 22 ; Lami's theorem , 23 ; polygon of forces , 25 ; Leibnitz's theorem , 26 ; converse of parallelogram of forces , 27 ; resultant of any system of forces in one plane , 28 ; of two parallel forces , 29 , 30 ...
... triangle of forces , 22 ; Lami's theorem , 23 ; polygon of forces , 25 ; Leibnitz's theorem , 26 ; converse of parallelogram of forces , 27 ; resultant of any system of forces in one plane , 28 ; of two parallel forces , 29 , 30 ...
Σελίδα vi
... triangle , perimeter of a triangle , 72 , 73 ; centre of gravity of a system of particles in a line , in a plane , arranged in any manner , 74 ; def . of moment of a force with respect to a plane , centre of mean position , centre of ...
... triangle , perimeter of a triangle , 72 , 73 ; centre of gravity of a system of particles in a line , in a plane , arranged in any manner , 74 ; def . of moment of a force with respect to a plane , centre of mean position , centre of ...
Σελίδα 19
... triangle of forces , was announced in the year 1586 by Stevinus of Bruges , without any strict proof of it . 22. The Triangle of Forces . If three forces acting at a point be represented in magnitude and direction by the sides of a triangle ...
... triangle of forces , was announced in the year 1586 by Stevinus of Bruges , without any strict proof of it . 22. The Triangle of Forces . If three forces acting at a point be represented in magnitude and direction by the sides of a triangle ...
Σελίδα 20
... triangle whose sides are parallel to the sides of ABC , we shall have by similar triangles : A'B ' : B'C ' : C'A ' = AB : BC : CA = P : Q : R. P B ' 23. From the parallelogram of forces we can easily de- duce the following theorem first ...
... triangle whose sides are parallel to the sides of ABC , we shall have by similar triangles : A'B ' : B'C ' : C'A ' = AB : BC : CA = P : Q : R. P B ' 23. From the parallelogram of forces we can easily de- duce the following theorem first ...
Σελίδα 24
... triangle ADB in which BD = AC we readily obtain sin CAD AB = AD sin BAC ' sin BAD AC = BD = AD sin BAC or if AD represents a force R , we conclude that a force R acting in a direction AD is equivalent to the two forces sin CAD R sin BAC ...
... triangle ADB in which BD = AC we readily obtain sin CAD AB = AD sin BAC ' sin BAD AC = BD = AD sin BAC or if AD represents a force R , we conclude that a force R acting in a direction AD is equivalent to the two forces sin CAD R sin BAC ...
Άλλες εκδόσεις - Προβολή όλων
Συχνά εμφανιζόμενοι όροι και φράσεις
accelerating force angular points applied axis balance ball bisects body or system centre of gravity circle coefficient of friction conditions of equilibrium cos² curve cycloid cylinder determine diagonal distance elastic equal particles equation equi find the centre fixed point forces acting fulcrum funicular geometrical given heavy particles Hence horizontal plane impact inclined plane latus rectum length lever librium magnitude and direction mass middle point moving parabola parallel parallelogram parallelogram of forces parallelopiped Pcos perpendicular polygon position of equilibrium pressure pully pyramid radius represented resolved rest resultant right angles rough shew sides similar triangles sin² sliding smooth sphere straight line string passes student suppose surface system of forces system of particles tangent tension theorem three forces tion triangle uniform vertex vertical plane virtual velocity W's virtual weight
Δημοφιλή αποσπάσματα
Σελίδα 15 - If two forces acting at a point be represented in magnitude and direction by the...