 | Elijah Galloway - 1829 - 890 σελίδες
...radius being 80 inches. 50 Ibs. X 10 feet X 18 inches 80 Inches _. ,—r =300 Ibs,—answer. PULLEY. Rule. Divide the weight to be raised by twice the number of pulleys, the quotient will give the power necessary to raise the weight. Example. What power is required to... | |
 | Samuel YOUNG (of Manchester.) - 1833 - 272 σελίδες
...the draft of the tube frame. ON BLOCKS AND PULLEYS. PROBLEM I. To find the power to raise the weight. RULE. Divide the weight to be raised by twice the num•ber of moveable pulleys, and the Quotient is the power to raise the weight. Two blocks having 3 pulleys or... | |
 | Joseph Denison - 1841 - 210 σελίδες
...weight by block-pulleys. Rule. — Divide the weight to be raised plus the weight of the lower block by twice the number of pulleys in the lower block ; the quotient will be the power required. EXAMPLES. 1. With a simple moveable pulley, what power will be sufficient to... | |
 | Joseph Denison - 1841 - 210 σελίδες
...weight by block-pulleys. Rule.—Divide the weight to be raised plus the weight of the lower block by twice the number of pulleys in the lower block ; the quotient will be the power required. EXAMPLES. 1. With a simple moveable pulley, what power will be sufficient to... | |
 | 1837 - 800 σελίδες
...the rigging of ships, where almost every motion is accomplished by its means. Examples on the Pulley. Rule. — Divide the weight to be raised by twice the number of moveable pulleys, and the quotient is the power required to raise the weight. Example 1. — What power... | |
 | John E. Fuller - 1846 - 82 σελίδες
...radius being 20 inches. 50 Ibs. multiplied by 10 ft. ; by 12 inches. = 300 Ibs. 20 inches. [Ans. PULLEY. RULE. — Divide the weight to be raised by twice...the power necessary to raise the weight. EXAMPLE. — What power is required to raise 600 Ibs., when the lower block contains six pulleys ? 600 = 50... | |
 | Septimus Norris - 1852 - 356 σελίδες
...the radius being 20 inches50 Ibs- x 10 feet x 12 inches 2Q inches- - = 300 Ibs-, Ans* PULLEYRULE — Divide the weight to be raised by twice the number...quotient will give the power necessary to raise the weightEXAMPLE — What power is required to raise 600 Ibs-, when the lower block contains six pulleys?... | |
 | Frederick Augustus Griffiths - 1854 - 406 σελίδες
...be taken out, before it is made use of, and it should enter easily into the grooves of the sheaves. Rule. — Divide the weight to be raised by twice...the power necessary to raise the weight. Example. — What power is required to raise 600 Ib., when the lower block contains six pulleys? 600-=50lb.... | |
 | Septimus Norris - 1854 - 334 σελίδες
...the radius being 20 inches. 50 Ibs. x 10 feet X 12 inches ^ — 20 inches. ~ = 3°° lbs- AnsPULLEY. RULE. — Divide the weight to be raised by twice...the power necessary to raise the weight. EXAMPLE. — What power is required to raise 600 Ibs., when the lower block contains six pulleys ? 600 6 x 2... | |
 | Septimus Norris - 1854 - 336 σελίδες
...being 20 inches. 50 Ibs. X 10 feet X 12 inches OA :^_@= 300 Ibs., Ans. 20 inches. PULLEY. EULE.@Divide the weight to be raised by twice the number of pulleys in the lower block; the quo tient will give the power necessary to raise the weight. EXAMPLE.@What power is required to raise... | |
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RULE. — Divide the weight to be raised by twice the number of pulleys in the lower block ; the quotient will give the power necessary to raise the weight. EXAMPLE. — What power is required to raise 600 Ibs., when the lower block contains six pulleys... 
