A Popular Course of Pure and Mixed Mathematics ...: With Tables of Logarithms, and Numerous Questions for Exercise |
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Σελίδα 160
A diameter of a circle is a straight line drawn through the centre , and terminated both ways by the circumference . 18. A semicircle is the figure contained by a diameter and the part of a circumference cut off by the diameter . 19.
A diameter of a circle is a straight line drawn through the centre , and terminated both ways by the circumference . 18. A semicircle is the figure contained by a diameter and the part of a circumference cut off by the diameter . 19.
Σελίδα 180
C D The opposite sides and angles of parallelograms are equal to one another , and the diameter bisects them , that is , divides them into two equal parts . N.B. A parallelogram is a four - sided figure , of which the opposite sides are ...
C D The opposite sides and angles of parallelograms are equal to one another , and the diameter bisects them , that is , divides them into two equal parts . N.B. A parallelogram is a four - sided figure , of which the opposite sides are ...
Σελίδα 182
it ; and the triangle DBC is the half of the parallelogram DBCF , because the diameter DC bisects it : but the halves of equal things are equal ; ( 7. Ar . ) therefore , the triangle ABC is equal to the triangle DBC .
it ; and the triangle DBC is the half of the parallelogram DBCF , because the diameter DC bisects it : but the halves of equal things are equal ; ( 7. Ar . ) therefore , the triangle ABC is equal to the triangle DBC .
Σελίδα 184
of the triangle ABC , because the diameter AC divides it into two equal parts ; wherefore ABCD is also double of the triangle EBC . Therefore , if a parallelogram , & c . Q.E.D. Proposition XLII . Problem . To describe a parallelogram ...
of the triangle ABC , because the diameter AC divides it into two equal parts ; wherefore ABCD is also double of the triangle EBC . Therefore , if a parallelogram , & c . Q.E.D. Proposition XLII . Problem . To describe a parallelogram ...
Σελίδα 185
... and produce HA , GB to the points L , M : Then HLKF is a parallelogram , of which the diameter is HK , and AG , ME are the parallelograms about HK ; and LB , BF are the complements : therefore LB is equal ( 43. 1. ) ...
... and produce HA , GB to the points L , M : Then HLKF is a parallelogram , of which the diameter is HK , and AG , ME are the parallelograms about HK ; and LB , BF are the complements : therefore LB is equal ( 43. 1. ) ...
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Συχνά εμφανιζόμενοι όροι και φράσεις
ABCD altitude axis base become called centre circle circumference co-efficient common cone consequently contained convergency curve denominator describe diameter difference distance divided draw drawn equal equation Examples expression factors feet figure fluxion four fraction function given gives greater half Hence infinite integral join less magnitudes manner measure meet meridian method Multiply opposite original parallel parallelogram pass perpendicular plane pole Prob probability Problem projection Prop proportional Proposition pyramid quantity radius ratio rectangle Reduce remaining represented result right angles root rule sides similar sine solid sphere square straight line subtract suppose taken tang tangent Theorem things third triangle vanishing whence Wherefore whole
Δημοφιλή αποσπάσματα
Σελίδα 172 - If, from the ends of the side of a triangle, there be drawn two straight lines to a point within the triangle, these shall be less than, the other two sides of the triangle, but shall contain a greater angle. Let...
Σελίδα 191 - If a straight line be divided into two equal parts, and also into two unequal parts, the rectangle contained by the unequal parts, together with the square on the line between the points of section, is equal to the square on half the line.
Σελίδα 190 - If a straight line be divided into any two parts, the rectangle contained by the whole and one of the parts, is equal to the rectangle contained by the two parts, together with the square of the aforesaid part.
Σελίδα 196 - AB be the given straight line ; it is required to divide it into two parts, so that the rectangle contained by the whole, and one of the parts, shall be equal to the square of the other part.
Σελίδα 192 - If a straight line be bisected and produced to any point, the rectangle contained by the whole line thus produced and the part of it produced, together •with the square on half the line bisected, is equal to the square on the straight line which is made up of the half and the part produced.
Σελίδα 177 - That, if a straight line falling on two straight lines make the interior angles on the same side less than two right angles, the two straight lines, if produced indefinitely, meet on that side on which are the angles less than the two right angles.
Σελίδα 209 - THE straight line drawn at right angles to the diameter of a circle, from the extremity of it, falls without the circle...
Σελίδα 284 - The bases of a cylinder are the circles described by the two revolving opposite sides of the parallelogram.
Σελίδα 286 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. either the sides adjacent to the equal...
Σελίδα 179 - Therefore all the angles of the figure, together with four right angles, are equal to twice as many right angles as the figure has sides.
Πληροφορίες βιβλιογραφίας
| Τίτλος | A Popular Course of Pure and Mixed Mathematics ...: With Tables of Logarithms, and Numerous Questions for Exercise |
| Συγγραφέας | Peter Nicholson |
| Εκδότης | G. B. Whittaker, 1825 |
| Πρωτότυπο από | το Πανεπιστήμιο του Μίτσιγκαν |
| Ψηφιοποιήθηκε στις | 11 Ιουν. 2007 |
| Μέγεθος | 372 σελίδες |
| Εξαγωγή αναφοράς | BiBTeX EndNote RefMan |