The new practical gager1820 |
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Αποτελέσματα 1 - 5 από τα 100.
Σελίδα 35
... SOLUTION . on B. on A. 28 : 98 £ 4 . 188. Ans . bu . sh . QUESTION 3 . - If 144lb . avoirdupois be equal to 175lb . troy , how many lb. troy are equivalent to 1 cwt . avoirdupois ? SOLUTION . lb. Av . lb. T. lb. Av . lb. T. As 144 : 175 ...
... SOLUTION . on B. on A. 28 : 98 £ 4 . 188. Ans . bu . sh . QUESTION 3 . - If 144lb . avoirdupois be equal to 175lb . troy , how many lb. troy are equivalent to 1 cwt . avoirdupois ? SOLUTION . lb. Av . lb. T. lb. Av . lb. T. As 144 : 175 ...
Σελίδα 75
... SOLUTION . 50 side of the square 50 side Product 2500 square inches , area sought . BY THE SLIDING RULE . Set 1 on B to 50 on A , and opposite to 50 on B will be found 2500 on A , for the area of the square . In like manner if the side ...
... SOLUTION . 50 side of the square 50 side Product 2500 square inches , area sought . BY THE SLIDING RULE . Set 1 on B to 50 on A , and opposite to 50 on B will be found 2500 on A , for the area of the square . In like manner if the side ...
Σελίδα 76
... and the breadth 42 inches ; the area is required . B 4.2 63 D SOLUTION . 63 length 42 breadth 126 252 Product 2646 square inches , area of the rectangle . BY THE SLIDING RULE . Set 1 on B to 76 MENSURATION OF SURFACES . Area of a Rectangle.
... and the breadth 42 inches ; the area is required . B 4.2 63 D SOLUTION . 63 length 42 breadth 126 252 Product 2646 square inches , area of the rectangle . BY THE SLIDING RULE . Set 1 on B to 76 MENSURATION OF SURFACES . Area of a Rectangle.
Σελίδα 77
... , whereof the base measures 76 inches , and the perpen- dicular from the base to the opposite side 70 inches ; the area is required . B E 76 D SOLUTION . 76 base of the MENSURATION OF SURFACES . 77 Area of a Parallelogram.
... , whereof the base measures 76 inches , and the perpen- dicular from the base to the opposite side 70 inches ; the area is required . B E 76 D SOLUTION . 76 base of the MENSURATION OF SURFACES . 77 Area of a Parallelogram.
Σελίδα 79
... SOLUTION . First way . 48 one side Second way . Third way . 24 half the base 48 base 15 half the other 30 perpendicular 30 perpendicular 720 product . 720 product . 2 ) 1440 product 720 half product . Wherefore the area of the given ...
... SOLUTION . First way . 48 one side Second way . Third way . 24 half the base 48 base 15 half the other 30 perpendicular 30 perpendicular 720 product . 720 product . 2 ) 1440 product 720 half product . Wherefore the area of the given ...
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Άλλες εκδόσεις - Προβολή όλων
Συχνά εμφανιζόμενοι όροι και φράσεις
30 inches A. G. divisor 282 ale gallons altitude area is required base bottom bung diameter Cask centre chord circular divisor circular gage-point Circular Segments conjugate diameter content is required Copper cross diameters crown cube cubic inches denomination determine the Content Diam diameter Multiply Dimension Book dipping place distance divide the product dividend division dry inches ellipsis equal EXAMPLE factor find the Area frustum Gage and Inch given figure given number greatest diameter inch deep inch in depth Lastly Let ABCD malt bushels mean diameter mean proportional measure middle mouth number of cubic opposite ordinates parabolic parallel perpendicular plane figure proposed integer quotient radius remainder required in wine Set the circular side SLIDING RULE SOLUTION Specific Gravity square inches square root straight line subtract sum Multiply tabular number tenths transverse diameter triangle ullage vulgar fraction Wet Inches Wherefore whole content wine gallons
Δημοφιλή αποσπάσματα
Σελίδα 39 - To draw a straight line perpendicular to a given straight line of an unlimited length, from a given point without it. Let AB be the given straight line, which may be produced to any length both ways, and let c be a point without it.
Σελίδα 27 - A diameter of a circle is a straight line drawn through the centre, and terminated both ways by the circumference.
Σελίδα 62 - Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product will be the area.
Σελίδα 56 - To measure a Parallelogram, or long square. RULE. Multiply the length by the breadth, and the product will be the area or superficial content.
Σελίδα 65 - TO FIND THE AREA OF A CIRCLE. Rule. — Multiply the square of the diameter by .7854 and the product will be the area.
Σελίδα xv - Separate the given number into periods of two figures each, beginning at the right hand: the period on the left will often contain but one figure.
Σελίδα 40 - To bisect a given finite straight line, that is, to divide it into two equal parts. Let AB be the given straight line : it is required to divide it intotwo equal parts.
Σελίδα 37 - At a given point in a given straight line, to erect a perpendicular to that line. Let AB be the given line and C the given point.
Σελίδα iii - EULE.—Divide as in whole numbers, and point off as many decimal places in the quotient as the number of decimal places in the dividend exceeds the number in the divisor.
Σελίδα 32 - A cylinder is conceived to be generated by the revolution of a rectangle about one of its sides as an axis.