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19. Add 69 acres, 2 roods, 1 rod; 76 acr. 3 ro. 39 rd.; 88 acr. 1 ro. 32 rd.; 150 acr. 3 ro. 29 rd.

20. Add 150 years, 221 days, 13 hours, 31 minutes, 29 seconds; 230 yr. 300 d. 23 h. 49 m. 59 s.; 191 yr. 149 d. 21 h. 39 m. 23 s.; 359 yr. 75 d. 23 h. 59 m. 19 s.

COMPOUND SUBTRACTION.

Art. 137.-1. If a picture-book cost 4d. and a spellingbook 11d., how much more does one cost than the other?

2. James bought a book for 9d. and sold it for 1s. How much did he gain by the bargain?

3. From 2s. 6d., take 1s. 8d.

4. From 8s. 9d. 3qrs., take 6s. 8d. 2qrs.

5. From 4 qts., take 3 pts.

6. If a bushel of rye be worth 7s. 6d., and a bushel of corn 6s. 4d., how much more is the rye worth than the corn?

7. How much more is wheat worth at 9s. 8d. per bushel, than corn at 7s. 6d. per bushel ?

8. How much more is 2 bushels 2 pecks, than 1 bushel 3 pecks?

9. From £29 9s. 6d. 3qrs., take £23 10s. 7d. 2grs.

Operation.

£ d. qrs. 29 9 6 3 23 10 7 2 1

In this example, we write the difference between 2 and 3 farthings in the line of farthings, and proceed to the column of pence; 5 18 11 we carry none, because we borrowed none-but 7d. from 6d. cannot be obtained; we therefore borrow as many pence as make a shilling, and say, 7 from 12-the remainder 5, we add to 6, in the upper line, and write 11 in the column of pence. We now carry 1 to the column of shillings, which is equal to the 12 pence we borrowed, and say, 11 from 9, which cannot be obtained; again we must borrow as many of the denomination we have to subtract as make one of the next higher, which is 20s., and say, 11 from 20, and 9 remain, which added to 9 in the upper

QUESTIONS.—1. What does Compound Subtraction teach? 2. Rule? 3. If the number in the upper line be less than the one standing under it, how may you proceed? 4. Why do you carry 1 to the next left-hand column?

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line, is 18, which must be written in the column of shillings. Lastly, the 20s. which we borrowed, we pay by carrying 1 to the line of pounds, which must be subtracted as in simple subtraction. Hence,

Art. 138.-COMPOUND SUBTRACTION teaches to find the difference between two compound sums, or quantities.

RULE.

I. Write the less number under the greater, so that numbers of the same denomination may stand directly under each other.

II. Begin to subtract with the lowest denomination, and také the lower line from the one above it; proceed in this way with all the denominations.

III. Should the number in the upper line be less than the one standing under it, borrow as many units as make 1 in the next higher denomination.

IV. From the units borrowed, subtract the lower number, and to the difference add the upper number; write their sum under the figures subtracted, observing to carry 1 to the next left-hand column.

Proof-The same as Simple Subtraction.

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11. From 31 tuns, 3 hhd. 15 gal., take 29 tuns, 2 hhd. 26 gal.

12. From 39 yds. 3 qr. 2 na., take 27 yds. 2 qr. 3 na. 13. From 127 E. E. 3 qr. 2 na., take 121 E. E. 4 qr. 3 na. 14. From 247 E. Fl. 0 qr. 2 na., take 159 E. Fl. 2 qr. 1 na. 15. From 671 E. Fl. 4 qr. 3 na., take 582 E. Fl. 5 qr. 2 na. 16. From 971 mi. 6 fur. 11 p. 3 yds. 1 ft., take 439 mi. 5 fur. 12 p. 4 yds. 2 ft.

17. From 69 acr. 2 ro. 31 rd., take 49 acr. 3 ro. 37 rd.

18. From 150 yrs. 221 d. 13 h. 31 m. 29 s., take 130 yrs. 129 d. 14 h. 39 m. 41 s.

19. From 260° 15 mi. 5 fur. 16 p. 13 ft. take 150° 17 m. 6 fur. 17 p. 12 ft.

20. From 240° 49′ 31′′ take 159° 59′ 41′′.

21. From 9s. 21° 31′ 42′′ take 7s. 22° 36′ 37′′.

22. A note dated Feb. 3d, 1826, was paid March 12th, 1837. How long was it from the first date until it was paid?

The time from one date to another may be found by subtracting the former date from the latter, observing to number the months in their order; thus, January, 1st month; February, 2d month, etc.

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OBS.-The month, in casting interest, is reckoned 30 days.

23. What is the time from June 3d, 1835, to July 15th, 1837? Ans. 2 yrs. 1 m. 12 d.

24. The latitude of a certain place is 42° 50′ north; that of another place is 39° 37′; what is the difference of latitude ? Ans. 3° 13'. 25. What is the difference of longitude between 39° 40′, and 29° 49' west? Ans. 9° 51'.

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As every circle, whether greater or less, is divided into 360 equal parts, or degrees, consequently, the circle described by the revolution of the earth on its axis every 24 hours, contains 360 equal parts, or degrees; and as 360 degrees are described in 24 hours, it is plain that in 1 hour, of 360, or 15 degrees, would be described; and, also, if 15 degrees be described in 1 hour, or 60 minutes, it is equally plain that 1 degree would be described in of 60 minutes, or in 4 minutes, and 1 minute of a degree in 4 seconds. Hence,

Art. 139.-To reduce longitude to time, we have the following

RULE.

Multiply the longitude in degrees and minutes by 4, and we have the time in minutes and seconds.

EXAMPLE.

Reduce 140 15' to time.

14° 15'

4

57′ 0′′ Ans.

Art. 140.—To find the difference of time between any two places, having the time of one place given, and their difference of longitude.

RULE

Reduce the longitude to time, and add it to the given time, if the longitude of the place whose time is required be east of the place whose time is given; and subtract it, if the longitude be

west.

OBS.-The reason of this is, because the farther we go east, the later is it in the day; and the farther west, the earlier in the day. That is, when it is 12 o'clock, at noon, in London, 15 degrees east of London it would be 1 o'clock, P. M.; and 15 degrees west of London it would be but 11 o'clock, A. M.

QUESTIONS.-5. How is the time from one date to another found? 6. How many degrees in a circle? 7. How many degrees does the earth describe in one hour, in its revolution round the sun? 8. In one minute? 9. In one second? 10. What is the rule for finding the difference of time between two places, the longitude being known?

26. When it is 12 o'clock in London, what is the hour in Boston, 70 degrees west longitude from London?

Ans. 7 o'clock 20 m.

27. When it is 12 o'clock in Boston, what is the time in London, lon. 70 deg. cast? Ans. 4 o'clock 40 m.

COMPOUND ADDITION AND SUBTRACTION.

ADDITION.

Art. 141.-1. A man bought a horse for £32 10s. and a pair of oxen for £24 11s. 6d. How much did both cost?

SUBTRACTION,

Art. 142.—2. If a pair of oxen and a horse cost £57 is. 6d. 2qrs., and the horse cost £32 10s., what was the cost of the oxen ?

3. If I purchase a farm for 4. If I sell a farm for £1150 £1092 4s. 8i., for how much | 4s. 4d., and gain £57 19s. 8d. by must I sell it to gain £57 19s. the bargain, what did the farm 8d.? cost?

5. A pipe of wine sprang aleak, and 31 gal. 1 qt. 1 pt. were lost, and there remained 86 gal. 2 qts. 1 pt. How many gallons were there at first?

7. There was a silver tankard which weighed 4 lbs. 3 oz., the lid weighed 6 oz. 4 pwt. 6 grs. How much did both weigh?

9. A merchant bought a quantity of sugar; sold 9 cwt. 3 qrs. 25 lbs.; had 7 cwt. 2 qrs. 17 lbs. left. How much did he buy?

11. From a piece of cloth were sold 6 yds. 2 qrs., and there remained 32 yds. 2 qrs. 2 na. How much was there at first?

13. A farmer has two mowing fields; one contains 8 acres, 3 ro., the other 12 acres, 2 ro. 24 rds. How many acres in both?

15. A note dated July 20, 1834, was paid in 9 mo. 46 d. At what time was it paid?

6. From a pipe of wine containing 118 gallons there leaked out 31 gal. 1 qt. 1 pt. How many remained?

8. If the weight of a silver tankard and lid be 4 lbs. 9 oz. pwt. 6 grs., and the lid alone weigh 6 oz. 4 pwt. 6 grs., what was the weight of the tankard?

10. A merchant bought 17 cwt. 2 qrs. 14 lbs. of sugar; sold 9 cwt. 3 qrs. 25 lbs. How much had he left ?

12. If from a piece of cloth containing 39 yds. 2 na., were sold 6 yds. 2 qrs., how many remained?

14. A farmer has two mowing fields, containing 31 acres, 1 ro. 24 rds.; one contains 12 acres, 2 ro. 24 rds. How many acres does the other contain?

16. A note dated July 20, 1834, was paid June 6, 1835. How long was it on interest?

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