| John Bonnycastle - 1813 - 456 σελίδες
...rale, Whence the numbers are 3, "¡, 11, and 15. 8. Itisrequired to find three numbers in geometrir cal progression^, such that their sum shall be 14, and the sum of their squares 84. Let x, y, and z be the three numbers, Then xz=y*, by the nature of proportion, ,, the Hence x + z=... | |
| John Bonnycastle - 1818 - 284 σελίδες
...consequently x=— 6+ </ (36 + 45) = — 6+9=3, by the rule, Whence the numbers are 3, 7, 11, and 15. 8. It is required to find three numbers in geometrical...sum shall be 14, and the sum of their squares 84. Let x, y, and z be the three numbers, Then xx=y3 , by the nature of proportion, y the question, . Hence... | |
| Jeremiah Day - 1820 - 352 σελίδες
...geometrical progression, may be solved, as in other parts of algebra, by the reduction of equations. Prob. 1. Find three numbers in geometrical progression, such...sum shall be 14, and the sum of their squares 84. Let the three numbers be x, y, and z. By the conditions, x:y::y:z, or xz=y3 And x+y+z=l4 And *a+y2+z*=84... | |
| John Bonnycastle - 1825 - 336 σελίδες
...consequently i= 6 + ^(36-4-45)= — 6+9=3, by the rule. Whence the numbers are 3, 7, 11, and 15. 8. It is required to find three numbers in geometrical progression, such that their sum shall be 14, anil the sum of their squares 84. Let x, y. and z he the three numbers, Then xz—y3, by the nature... | |
| Peter Nicholson - 1825 - 1046 σελίδες
...-аг" 3|0_3(Э'°— а") »(Д9049— 1024) *- r— I ~ 1— г ~~ _2 "~ 3le " ~ 59049 " 59049 3. Find three numbers in geometrical progression, such, that their sum shall be equal to 7, and the gum of their squares to 21. Let the numbers be «»y, and z; then by question And... | |
| Jeremiah Day - 1827 - 352 σελίδες
...geometrical progression, may be solved, as in other parts of algebra, by the reduction of equations. Prob.l. Find three numbers in geometrical progression, such...sum shall be 14, and the sum of their squares 84* Let the three numbers be x, y and z. By the conditions x : y. '.y : z, or xz=y3 i And x+y+z = l4> And... | |
| Alexander Ingram - 1830 - 458 σελίδες
...third, and so on. In what time will he overtake the first ? oix _ i -^ — * = (*+7)9. Ans. 18 days. 7- To find three numbers in geometrical progression, such, that their sum shall be , . and the sum of their squares 21. Liet x, y, 2, be the numbers. xz=y*, x+y + z = J, aa+y* + z* =21.... | |
| Jeremiah Day - 1832 - 360 σελίδες
...geometrical progression, may be solved, as in other parts of algebra, by the reduction of equations. Prob. 1. Find three numbers in geometrical progression, such that their sum shall be 14, and the sum of thensquares 84. Let the three numbers be x, y, and z. By the conditions, x :y : :y : z, or xz=yl And... | |
| John Bonnycastle - 1836 - 296 σελίδες
...numbers are 3, 7, 11, and 15. 8. It is required to find three numbers iu geometrical progression, Mich that their sum shall be 14, and the sum of their squares 84. Let x, y, and z, be the three numbers, then xz—y1, by the nature of the progression. y the hence... | |
| John Radford Young - 1839 - 332 σελίδες
...— 4, or — 10 : hence the three numbers are 5, 9, and 19 ; or rather 19, 9, and 5. QUESTION II. It is required to find three numbers in geometrical...sum shall be 14, and the sum of their squares 84. Let -, x, and xy, be the three numbers ; У then, by the question, - + x + xy = 14, У .-. from the... | |
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